The balanced reaction equations are;
a) 4 NaClO + H2S → 4 NaCl + H2SO4
b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O
<h3>What is a balanced redox reaction?</h3>
A redox reaction is said to be balanced when the number of electrons gained is equal to the number of electrons lost.
Let us now write the balanced reaction equations one after the other. Thus;
a) 4 NaClO + H2S → 4 NaCl + H2SO4
b)6Ce^4+ + I^– + 6OH^– → 6 Ce^3+ + IO3^– + 3H2O
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1 mol of any particles = 6.02*10²³ particles
56 mol*6.02*10²³ molecules of water/1 mol =3.37*10²⁵
Salt lowers the freezing/melting point of water, so in both cases the idea is to take advantage of the lower melting point. Ice forms when the temperature of water reaches 32 degrees Fahrenheit (0 degrees Celsius).
Answer:
13.20
Explanation:
Step 1: Calculate the moles of Ba(OH)₂
The molar mass of Ba(OH)₂ is 171.34 g/mol.
0.797 g × 1 mol/171.34 g = 4.65 × 10⁻³ mol
Step 2: Calculate the molar concentration of Ba(OH)₂
Molarity is equal to the moles of solute divided by the liters of solution.
[Ba(OH)₂] = 4.65 × 10⁻³ mol/60 × 10⁻³ L = 0.078 M
Step 3: Calculate [OH⁻]
Ba(OH)₂ is a strong base according to the following equation.
Ba(OH)₂ ⇒ Ba²⁺ + 2 OH⁻
The concentration of OH⁻ is 2/1 × 0.078 M = 0.16 M
Step 4: Calculate the pOH
pOH = -log OH⁻ = -log 0.16 = 0.80
Step 5: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - 0.80 = 13.20
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