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Zielflug [23.3K]
3 years ago
7

What are two main forms of energy given off when paper burns and where does the energy come from

Chemistry
2 answers:
galina1969 [7]3 years ago
5 0
When paper burns, it releases two distinct forms of energy
Thermal Energy
Light Energy

Thermal Energy is heat energy, heat energy is formed from the flame on the paper, in this scenario. 

Light energy comes from the reaction of the paper, the flame.

In conclusion, both energy's form from the reaction of the paper, and the combustion in the air. Thus, heat and light.
luda_lava [24]3 years ago
3 0
Thermal energy and light energy
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What is the total number of atoms in the formula<br> Ca(ClO3)2?
Contact [7]

Answer:

9 atoms

Explanation:

Ca=1

Cl=2

O=6

add them all

5 0
3 years ago
Read 2 more answers
Identify the acids and the bases in the chemical equation ​
agasfer [191]
<h3><u>Answer;</u></h3>

Acids;  HCl and HC5H5N+

Bases; C5H5N and Cl-

<h3><u>Explanation;</u></h3>
  • According to Bronsted-Lowry Theory an acid is a proton or hydrogen ion donor while a base is a proton or a hydrogen ion acceptor.
  • In this case,<u> both HCl and HC5H5N+ are acids</u> as <u>they are donors of hydrogen ions</u>. HCl is an acid to the forward reaction while HC5H5N+ is a acid to the reverse reaction.
  • On the other hand, <u>C5H5N and Cl- are bases</u>, <u>they are acceptors of hydrogen  ions</u>. Cl-  is a base in the reverse reaction while C5H5N is a base in the forward reaction.
8 0
3 years ago
Calculate the acid dissociation constant Ka of a 0.2 M solution of weak acid that is 0.1% ionized is ________.
mars1129 [50]

Answer: acid dissociation constant Ka= 2.00×10^-7

Explanation:

For the reaction

HA + H20. ----> H3O+ A-

Initially: C. 0. 0

After : C-Cx. Cx. Cx

Ka= [H3O+][A-]/[HA]

Ka= Cx × Cx/C-Cx

Ka= C²X²/C(1-x)

Ka= Cx²/1-x

Where x is degree of dissociation = 0.1% = 0.001 and c is the concentration =0.2

Ka= 0.2(0.001²)/(1-0.001)

Ka= 2.00×10^-7

Therefore the dissociation constant is

2.00×10^-7

7 0
2 years ago
A saturated solution can become supersaturated under which of the following conditions
Kaylis [27]

the answer is d. when more solute is added

5 0
2 years ago
A gas at constant temperature has a pressure of 404.6 kPa with a volume of 12 ml. If the volume changes to 43ml, what is the new
blagie [28]

Answer:

The answer is

<h2>112.912 kPa</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

404.6 kPa = 404600 Pa

From the question we have

P_2 =  \frac{404600 \times 12}{43}  =  \frac{4855200}{43}  \\  = 112911.6279... \\  = 112912

We have the final answer as

<h3>112.912 kPa</h3>

Hope this helps you

4 0
3 years ago
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