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Bad White [126]
3 years ago
13

Please help me whoever does help me gets 16 points just please help me

Chemistry
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

The answer is A.

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When calcium reacts with tellurium to form an ionic compound, each metal atom loses electron(s) and each nonmetal atom gains ele
Finger [1]

Answer:

When calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

There must be 1 calcium atom for every 1 tellurium atom in the reaction.

Explanation:

Calcium has atomic number of 20. Its electronic configuration is given as:

[Ca]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2

Calcium atom will loose 2 elections to attain electronic configuration of noble gas.

[Ca^{2+}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^0

Ca\rightarrow Ca^{2+}+2e^-

Tellurium has atomic number of 52. Its electronic configuration is given as:

[Te]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p4

Tellurium atom will gain 2 elections to attain electronic configuration of noble gas.

[Te^{2-}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p6

Te+2e^-\rightarrow Te^{2-}

So, when calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

Ca^{2+}+Te^{2-}\rightarrow CaTe

There must be 1 calcium atom for every 1 tellurium atom in the reaction.

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