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almond37 [142]
3 years ago
7

At 100.0∘C, the ion product of water is 5.13×10−13. What is the concentration of hydroxide ions at this temperature? Your answer

should include three significant figures. Write your answer in scientific notation. Use the multiplication symbol rather than the letter x in your answer.
Chemistry
1 answer:
Trava [24]3 years ago
6 0

Answer: The concentration of hydroxide ions at this temperature is 7.16\times 10^{-7}

Explanation:

When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.

The ionic product for water is written as:

K_w=[H^+][OH^-]

5.13\times 10^{-13}=[H^+][OH^-]

As [H^+]=[OH^-]

5.13\times 10^{-13}=x^2

x=7.16\times 10^{-7}

The concentration of hydroxide ions at this temperature is 7.16\times 10^{-7}

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Answer:

1.67 moles

Explanation:

From the balanced equation of reaction:

                     SO_2 + 2H_2S -> 3S + 2H_2O

1 mole of sulfur dioxide, SO2, is required to produce 3 moles of sulfur, S.

<em>If 1 mole SO2 = 3 moles S, then, how many moles of SO2 would be required for 5 moles S?</em>

     Moles of SO2 needed = 5 x 1/3

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Hence, <u>1.67 moles of SO2 would be required to produce 5.0 moles of S.</u>

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2 years ago
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A compound is 52.0% zinc 9.6% carbon and 38.4% oxygen. Calculate the empirical formula of the compound.
skad [1K]

Answer:

So a compound is 52% Zinc(Zn), 9.6% Carbon(C), and 38.4% Oxygen (O). Let’s first start off by assuming that we have 100 g of this compound. This means that we have 52 g of Zinc, 9.6 g of Carbon, and 38.4 g of Oxygen.Zinc = 65.38 g/molCarbon = 12 g/molOxygen = 16 g/molThis means we have:52 g of Zn(1 mol Zn/65.38 g of Zn) ≈0.8 mol of Zn.9.6 g of C(1 mol C/12 g of C) = 0.8 mol of C38.4 g of O(1 mol of O/16 g of O) = 2.4 mol of O.

Explanation:

What we want to do next is divide each element by the common factor of all of them, which is 0.8. In most cases, you divide each element by the element with the least amount of moles. After we divide each by 0.8, you’ll notice you have 1 Zn, 1 C, and 3 O. This gives you the empirical formula of ZnCO3, or Zinc Carbonate.

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