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dangina [55]
3 years ago
9

Which describes the heliocentric model of the solar system? (1 point)

Chemistry
1 answer:
maw [93]3 years ago
6 0

Answer:

D

Explanation:I alredy know this i am in 7th gread

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The density of a metal is 10.5 g/cm3. If the mass of themetal
vitfil [10]

Answer:

11.7 mL

Explanation:

Density of a substance is given by the mass of the substance divided by the volume of the substance .

Hence , d = m / V

V = volume

m = mass ,  

d = density ,

From the question ,

The density of the metal = 10.5 g/cm³

The mass of the metal = 5.25 g

Hence , the volume can be calculated from the above formula , i.e. ,

d = m / V  

V = m / d

V = 5.25 g / 10.5 g/cm³

V = 0.5 cm³

Since , The unit 1 mL = 1 cm³

V = 0.5 mL

The vessel has 11.2 mL of water ,

The new volume becomes ,

11.2 mL +  0.5 mL = 11.7 mL

4 0
4 years ago
The space shuttle heats up during reentry. Which term best describes what is causing
Korvikt [17]
The answer is Velocity .
6 0
3 years ago
What kind of energy can be transferred?<br><br> Help quick please.
defon

Answer:

Any kind, as long as there is an action.

7 0
3 years ago
Read 2 more answers
what is the molarity of a RbOH solution if 60.0 mL of the solution is neutralized by 52.8 mL of a 0.5M HCl solution (Hint: Ma x
Dahasolnce [82]
RbOH is a strong base that dissociates completely and HCl is a strong acid that too dissociates completely. the complete reaction between the acid and base is;
RbOH + HCl ---> RbCl + H₂O
stoichiometry of acid to base is 1:1
At neutralisation point
H⁺ mol = OH⁻ mol
mol = molarity x volume 
if Ma - molarity of acid and Va - volume of acid reacted
Mb - molarity of base and Vb - volume of base reacted 
Ma x Va = Mb x Vb
0.5 M x 52.8 mL = Mb x 60.0 mL 
Mb = 0.44 M 
molarity of base - 0.44 M 

7 0
3 years ago
URGENT!! Can someone please explain this to me?
djverab [1.8K]

Answer:

CH _{4}+ 2O  _{2} → CO _{2} + 2H _{2}O

for the balanced equation

from \: the \: equation \\ 1 \: mole \: of \: methane \: gives \: 1 \: mole \: of \: carbon \: dioxide \\ 7.4 \: moles \: of \: carbon \: dioxide \: will \: be \: given \: by \: (7.4 \times 1)moles \: of \: methane \\  = 7.4\: moles \: of \: methane \\  \\  since \: moles \: of \: oxygen \: double \: those \: of \: methane \\ moles \: of \: oxygen \:  = 7.4\times 2 \\  = 14.8 \: moles \: of \: oxygen

4 0
3 years ago
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