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Olegator [25]
3 years ago
7

Help with this chemistry question please???

Chemistry
1 answer:
givi [52]3 years ago
6 0
To find percent composition, you should first find the total of all of the components. Just add them all together:

100g+200g+50g=350g

Then, divide the amount of the component you are interested in, in this case, chocolate (50g), by the total amount to give:

\frac{50g}{350g}

This will give you the answer in decimal form, but to convert to a percent, you need to multiply by 100:

\frac{50g}{350g}*100

Therefore, the answer choice that is correct is A.
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Which type of precipitation is shown in the diagram below? How does this precipitation form?
Kisachek [45]

Answer:

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Explanation:

i knew this alr

3 0
2 years ago
A gas will stay dissolved in solution best
m_a_m_a [10]
A. (cold solutions hold on to their solutes better)
5 0
3 years ago
Find the density of metal with a volume 4.0 cm and a mass of 8.0 grams.
olga_2 [115]
D=m/v

so,

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3 0
3 years ago
If 1.76 g of an ideal gas occupy 1.0 L at standard temperature and pressure (STP), what is the molar mass of the gas?
ycow [4]

Answer:

Explanation:

Whenever you see molar masses in gas law questions, more often than not density will be involved. This question is no different. To solve this, however, we will first need to play with the combined ideal gas equation PV=nRT to make it work for density and molar mass. The derivation is simple but for the sake of time and space, I will skip it. Hence, just take my word for it that you will end up with the equation:M=dRTPM = molar mass (g/mol)d = density (g/L)R = Ideal Gas Constant (≈0.0821atm⋅Lmol⋅K) T = Temperature (In Kelvin) P = Pressure (atm)As an aside, note that because calculations with this equation involve molar mass, this is the only variation of the ideal gas law in which the identity of the gas plays a role in your calculations. Just something to take note of. Back to the problem: Now, looking back at what we're given, we will need to make some unit conversions to ensure everything matches the dimensions required by the equation:T=35oC+273.15= 308.15 KV=300mL⋅1000mL1L= 0.300 LP=789mmHg⋅1atm760mmHg= 1.038 atmSo, we have almost everything we need to simply plug into the equation. The last thing we need is density. How do we find density? Notice we're given the mass of the sample (0.622 g). All we need to do is divide this by volume, and we have density:d=0.622g0.300L= 2.073 g/LNow, we can plug in everything. When you punch the numbers into your calculator, however, make sure you use the stored values you got from the actual conversions, and not the rounded ones. This will help you ensure accuracy.M=dRTP=(2.073)(0.0821)(308.15)1.038= 51 g/molRounded to 2 significant figuresNow if you were asked to identify which element this is based on your calculation, your best bet would probably be Vandium (molar mass 50.94 g/mol). Hope that helped :) 

8 0
2 years ago
Is baking cake a acid base reaction
Zinaida [17]
When baking powder is added to a cake, the acid base reaction it undergoes with the acidic butter produces the carbon dioxide that makes the cake rise.
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