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3 years ago

Which of the following is the Lewis structure for CO2?

Chemistry

1 answer:

velikii [3]3 years ago

4 0

Answer:

The CO2 Lewis structure has two double bonds going from carbon to the oxygen atoms. According to the octet rule, each oxygen atom needs to bond twice and the carbon atom needs to bond four times.

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Which of the following is true for balancing equations?

algol [13]

Answer:

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

The law of conservation of matter asserts that no observable and empirical change in the amount of matter occurs within a conventional chemical process. As a result, each element in the product would have the same equal amount or numbers of atoms as the reactants.

5 0

3 years ago

What does the triple point on a phase diagram describe

cluponka [151]

It describes the point at which the element is a solid liquid and has at a certain temperature and pressure

7 0

3 years ago

A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.

julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

4 0

4 years ago

5. The heat of fusion of lead is 25 J/g and its melting point is 601 K. How much heat is given off as 3.0 g

PIT_PIT [208]

Answer:

the heat given off is 75 J.

Explanation:

Given;

latent heat of fusion of lead, L= 25 J/g

mass of liquid lead, m = 3.0g

The heat given off is calculated as;

H = Lm

Where;

H is the quantity of heat given off

H = 25 x 3

H = 75 J.

Therefore, the heat given off is 75 J.

5 0

3 years ago

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu

vlabodo [156]

Answer is 30.0mL

according to the question dilution is performed by the student which can be calculated with the help of :

$M_{1}V_{1}=M_{2}V_{2}$ EQUATION (1)

Here, we have:

$M_{1}$ = 3M

$V_{1}$ = y mL

$M_{2}$ = 1.80 M

$V_{2}$ = 50.0mL

putting the known values in equation (1) which will give us value of $V_{1}$

3.00× y =1.80 ×50.0

y= 30.0mL

3 0

4 years ago

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