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Answer i) The molarity for the solution of 
prepared after dilution from 10 mL of 0.33 M solution to 1 L solution is 3.3 X 
,
by using this formula.
So, Molarity of unknown solution = (10 X 0.33) / 1000 = 3.3 X.
Answer ii) When you dilute the solution prepared in question (1 ) to 50.0 mL from 5.00 mL of 1L solution then, you should take an aliquot of 5 mL and then dilute upto 50 mL that will be the result of another 10 times dilution which will result in the new concentration as 0.00033 M for solution.
Answer iii)
Question iii is incomplete. Complete question is attached below;
Solution:
Given: A = 0.982, b = 1 cm, c = 0.0001 M
we know that, A = ebc
Therefore, ∈ = A/bc = 0.982/(1 X 0.0001) = 9820 M-1 cm-1.
Thus, molar absorptivity of solution is 9820 M-1 cm-1.
So, Molarity of unknown solution = (10 X 0.33) / 1000 = 3.3 X
Answer ii) When you dilute the solution prepared in question (1 ) to 50.0 mL from 5.00 mL of 1L solution then, you should take an aliquot of 5 mL and then dilute upto 50 mL that will be the result of another 10 times dilution which will result in the new concentration as 0.00033 M for
Answer iii)
Question iii is incomplete. Complete question is attached below;
Solution:
Given: A = 0.982, b = 1 cm, c = 0.0001 M
we know that, A = ebc
Therefore, ∈ = A/bc = 0.982/(1 X 0.0001) = 9820 M-1 cm-1.
Thus, molar absorptivity of solution is 9820 M-1 cm-1.