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Answer:
Lewis structure for nitrogen triiodide, is given in the attachment.
Explanation:
Given:
The given compound is Nitrogen triiodide. In which 1 atom of Nitrogen combines with 3 atoms of Iodine. Both Nitrogen and Iodine are non-metals,So they form covalent bond by sharing of electrons.
The electron configuration of Nitrogen and Iodine is given below;
There are 5 electrons in valance shell of Nitrogen atom and 7 electrons in valance shell of Iodine atom.
So, 3 atom of Iodine shares 1 electron with 1 electrons of Nitrogen.
The Lewis dot Structure is in the attachment.
Answer:
C) 5.6
Explanation:
From Henderson-Hasselbalch equation:
A = Conjugate base, HA = Acid
%A = 0.251 / (0.251 + 0.1) = 20%, hence %HA = 80%
100 mL of a 0.2 M = 0.02 mol
base = 20% of 0.02 = 0.004
Acid = 80% of 0.02 = 0.016
0.004 moles of base will get protonated by .004 moles of H+ from HCl, forming 0.004 moles of acid
0.02mol original acid - .004 mol H+ = 0.016 mol of conjugate base
Hence A/HA = 0.016/0.004
Since the new pH is 6.2, therefore: