Pb(NO3)2(aq) + K2SO4(aq) --> PbSO4(s) + 2KNO3(aq)
<span>Total ionic equation: </span>
<span>Pb 2+ (aq) + 2NO3- (aq) + 2K+ (aq) + SO4 2- (aq) ---------> PbSO4 + 2K+ (aq) + 2NO3- (aq) </span>
<span>For the net ionic equation cancel out species found on both sides to get: </span>
<span>Pb 2+ (aq) + SO4 2- (aq) ----------> PbSO4(s) </span>
<span>Note aqueous species dissolve and are separated into their ions but solid ones do not and simply precipitate out of solution.</span>
Answer:
[H+] = 1.74 x 10⁻⁵
Explanation:
By definition pH = -log [H+]
Therefore, given the pH, all we have to do is solve algebraically for [H+] :
[H+] = antilog ( -pH ) = 10^-4.76 = 1.74 x 10⁻⁵
Where the width is narrow and the bottom steep
B. Folds
Hope that helps! :)
False. It is used to show the Ph of something.
