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3 years ago

How to solve 2=-log(x)

Chemistry

1 answer:

ch4aika [34]3 years ago

8 0

First, you want to extract the negative from -log(x).

So now you have log(x) = -2

Now you have to use the property loga(x)=b is the same as x=a^2

So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.

Then you evaluate the negative square to 1/10^2

Answer is 1/100

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Define Acid and alkalis

kicyunya [14]

Answer:

Acids have a pH less than 7. Acids contain lots of hydrogen ions

Alkalis have a pH greater than 7. Alkalis contain lots of hydroxide ions

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7 0

2 years ago

Read 2 more answers

DUPLICATE. The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to

Law Incorporation [45]

At the half equivalence point [HA] = [A-] and pH = pKa

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3 years ago

The activation energy of a certain uncatalyzed reaction is 64 kJ/mol. In the presence of a catalyst, the Ea is 55 kJ/mol. How ma

Ksivusya [100]

Answer:

About 5 times faster.

Explanation:

Hello,

In this case, since the Arrhenius equation is considered for both the catalyzed reaction (1) and the uncatalized reaction (2), one determines the relationship between them as follows:

$\frac{k_1}{k_2}=\frac{Aexp(-\frac{Ea_1}{RT} )}{Aexp(-\frac{Ea_2}{RT})} \\\frac{k_1}{k_2}=\frac{exp(-\frac{Ea_1}{RT} )}{exp(-\frac{Ea_2}{RT})}$

By replacing the corresponding values we obtain:

$\frac{k_1}{k_2}=\frac{exp(-\frac{55000J/mol}{8.314J/molK*673.15K} )}{exp(-\frac{64000J/mol}{8.314J/molK*673.15K} )} =4.8$

Such result means that the catalyzed reaction is about five times faster than the uncatalyzed reaction.

Best regards.

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3 years ago

How glass tube filed with acidified potassium dichromate detect drunken driver

hodyreva [135]

Answer:

See explanation

Explanation:

The reaction between alcohol and acidified potassium dichromate is a redox reaction. This reaction can be used to detect a drunken driver.

Alcohols can be oxidized to aldehydes, ketones and carboxylic acids depending on the structure of the alcohol. Primary alcohols yield adehydes and carboxylic acids while secondary alcohols are oxidized to ketones.

The colour of the acidified potassium dichromate turns from orange to green when exposed to alcohols from the breath of a drunken driver.

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3 years ago

I cant help you with math and science homework or project just email at shahlaalgow g mail com

Kisachek [45]

Answer:

thanks

Explanation:

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3 years ago