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chubhunter [2.5K]
3 years ago
9

How to solve 2=-log(x)

Chemistry
1 answer:
ch4aika [34]3 years ago
8 0

First, you want to extract the negative from -log(x).

So now you have log(x) = -2

Now you have to use the property loga(x)=b is the same as x=a^2

So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.

Then you evaluate the negative square to 1/10^2

Answer is 1/100

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Infectious agents vary in their size and shape. Which infectious agent tends to be the smallest?
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Answer:

prions

Explanation:

They are the smallest infectious agent.

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3 years ago
5 What is the concentration of a 25.0 mL HCl solution containing a phenolphthalein indicator that is titrated with 0.1 M NaOH if
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The correct answer is 0.137 M.

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3 years ago
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In part A, when you added water to the sodium acetate in the flask, some of the chemical dissolved into the water. Would you cal
viktelen [127]

Answer: The solution is a SATURATED solution.

Explanation:

Although most substances are soluble in water, some are more soluble than others,that is , their solubilities differ. SOLUBILITY is a means of comparing the extent to which different solutes can dissolve in a particular solvent at a definite temperature.

From the question above, when water was added to the sodium acetate in the flask, SOME of the chemical dissolved into the water, meaning that some remained undissolved. This is because a given volume of water can only dissolve a certain amount of chemical in it at room temperature. If more chemical is added to such a solution, the chemical will remain undissolved. Such a chemical solution is said to be a SATURATED SOLUTION.

A saturated solution of a solute at a particular temperature is on which contains as much solute as it can dissolve at that temperature in the presence of undissolved solute particles.

Unsaturated solution is a type of solution that dissolves all its solutes with no presence of undissolved solute.

Supersaturated solution is one which contains more of the solute than it can normally hold at that temperature. It is an unstable solution which crystallizes out when disturbed.

4 0
3 years ago
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A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori
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Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

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where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of metal = 129.00 g

m_2 = mass of water = 45.00 g

T_f = final temperature = 39.6^oC

T_1 = initial temperature of metal = 97.8^oC

T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

c_1=0.481J/g^oC

Therefore, the specific heat of metal is 0.481J/g^oC.

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Determine the frequency of light with a wavelength of 2.672 x 10^-7cm
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Determine the frequency of light with a wavelength of 2.775⋅10−7 cm. Answer in units of Hz?❤

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