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lara [203]
3 years ago
13

How is modern dance different from ballet?​

Physics
2 answers:
Valentin [98]3 years ago
6 0

Answer:

Modern dance is all about the natural movement of the body, different styles are created to a person's body movement, whereas for ballet a dance is created and you can either do it or you cannot. ... Ballet compared to modern dance is very strict and straight-forward, modern dance reflects on the opposite of ballet.

Explanation:

Hope it helps

RSB [31]3 years ago
4 0

Answer:you eat caca

Explanation:

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A copper wire 20 m long and 4mm in diameter is attached to the Ceiling and a 400 N
Fiesta28 [93]

Answer:

A

Explanation:

5 0
2 years ago
The force of the added water produces a torque on the dam. In a simple model, if the torque due to the water were enough to caus
Fittoniya [83]

Answer:

The appropriate response is "\tau=\frac{1}{6} PgLh^3". A further explanation is described below.

Explanation:

The torque (\tau) produced by the force on the dam will be:

⇒  d \tau=XdF

On applying integration both sides, we get

⇒  \tau = \int_{0}^{a}x pgL(h-x)dx

⇒     = pgL\int_{0}^{h}(h-x)dx

⇒     =pgL[\frac{h^3}{2} -\frac{h^3}{3} ]

⇒     =\frac{1}{6} PgLh^3

8 0
2 years ago
Please list them from top to bottom, for exp like in your response, a,g,q,d. Giving quite some points for it.
Aleks04 [339]
D,f,g,h,i,a,e,c,j. I’m sure that it
7 0
2 years ago
How rolling friction is less than sliding friction?
vovangra [49]

Rolling friction is considerably less than sliding friction as there is no work done against the body that is rolling by the force of friction. For a body to start rolling a small amount of friction is required at the point where it rests on the other surface, else it would slide instead of roll.

6 0
3 years ago
The Hubble Space Telescope was released from the Space Shuttle, which was in a circular orbit at 400km earth altitude. The relat
snow_lady [41]

Answer:

d = (75 i ^ + 93 j ^ + 27 k ^) m ,  d2 = (900 i ^ + 1116 j ^ + 324 k ^) m

Explanation:

The two objects are in circular orbit together, therefore with the same angular velocity, after the launch they move with the relative velocity, so we can use the kinematic relation

       

         v = d / t

         d = v t

Reduce time to units SI

         t = 5 min (60 s / 1 min) = 300 s

X axis

         x = vₓ t

         x = 0.25 300

         x = 75 m

Y axis  

        y = v_{y} t

        y = 0.31 300

       y = 93 m

Z axis

        z=  v_{z} t

        z = 0.09 300

       z = 27 m

       d = (75 i ^ + 93 j ^ + 27 k ^) m

For the time of 1 h

       t2 = 1 h (3600s / 1 h) = 3600

       x2 = 900 m

       y2 = 1116 m

       z2 = 324 m

      d2 = (900 i ^ + 1116 j ^ + 324 k ^) m

5 0
3 years ago
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