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Tom [10]
3 years ago
5

You lift a stuffed toy up above the ground (over your head).

Physics
1 answer:
BigorU [14]3 years ago
7 0

Answer:

Gravitational energy

Explanation:

when over head , when it hits the floor thermal energy

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Identify the three types of isometric transformations. A. reflection, rotation, translation B. reflection, rotation, dilation C.
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The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 8.55 g of conden
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Answer:

m = 62.14 g

Explanation:

Energy used to melt the ice is the energy released by the condensation of the water forms on the glass

so here we have

energy for the condensation of water is given as

let mass of water condensed = m

E = m_1 L_f

now the energy of vaporization is given as

E = m_2 L_v

here we know that

L_f = 79.8 kCal/kg

L_v = 580 k Cal/kg

Now we have

8.55 \times 580 = m \times 79.8

m = 62.14 g

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3 years ago
Which of the following statements about features on the sun is true
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Explain how a compass works using scientific terminology.
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2 years ago
Read 2 more answers
A 13561 N car traveling at 51.1 km/h rounds
Minchanka [31]

Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

a_{c} = \frac{v^{2}}{r}

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2}

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

F_{c} = ma_{c}

Where:

m: is the mass of the car

The mass is given by:

P = m*g

Where P is the weight of the car = 13561 N

m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg

Now, the centripetal force is:

F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

F_{c} = F_{\mu}

F_{c} = \mu N = \mu P

\mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!                

3 0
3 years ago
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