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STatiana [176]
3 years ago
8

When the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0 * 10-4 T. What is the radius of the l

oop?
Physics
1 answer:
Leona [35]3 years ago
5 0

Answer:

ill get back to this question once i get the answer

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If the balloon can barely lift an additional 3500 N of passengers, breakfast, and champagne when the outside air density is 1.23
Bingel [31]

The complete question is :

A hot-air balloon has a volume of 2100 m3 . The balloon fabric (the envelope) weighs 860 N . The basket with gear and full propane tanks weighs 1300 N .

If the balloon can barely lift an additional 3400 N of passengers, breakfast, and champagne when the outside air density is 1.23kg/m3, what is the average density of the heated gases in the envelope?

Solution :

Given volume of the hot air balloon $=2100 \ m^3$

The balloon fabric weights = 860 N

The weight of the basket with the gear and propane tank = 1300 N

Density of outside air $= 1.23 \ kg/m^3$

∴  Total pay load = Weight of the air displaced - weight of gas inside the balloon

Total pay load = 860 + 1300 + 3400

                        = 5560 N

Mass = density x volume

Weight  $= \text{mass} \times g$

Weight = volume x density $\times \text{ acceleration due to gravity (g)}$

Weight of the displaced air = 2100 x 1.23 x 9.8

                                             = 25313 N

Weight of the gas inside the balloon = density $\times \text{ acceleration due to gravity (g)}$ x volume

                                                             = density x 9.8 x 2100

                                                             = density x 20580 N

Therefore substituting the values, we get

⇒ 25313 - (density x 20580) = 5560

⇒ density $=\frac{19753}{20580}$

                 $= 0.96 \ kg/m^3$

So the density of the heated gas $= 0.96 \ kg/m^3$

8 0
3 years ago
Why did scientists using classical, Newtonian physics have difficulty explaining the photoelectric effect?
Ganezh [65]
Classical physics considered light to behave as a wave in all environments; it had a set amplitude, frequency etc. The problem was that this meant that there was a continuous variation in its properties, hence if the amplitude of the light was incresed by a bit, a phenomenon like the phhotoelectric one would become only marginally more apparent. However, in this case, there is a cutoff point which means that the only-wave theory had to be wrong.
3 0
3 years ago
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Quando e como surgiu a ginastica rítmica no mundo e no Brasil?
Otrada [13]
A ginástica rítmica no Brasil começou a ser praticada na década de 1960. Teve várias denominações, entre elas foi chamada de ginástica moderna e ginástica rítmica moderna e, sendo praticada essencialmente por mulheres, passou a ser chamada de ginástica feminina moderna. Depois, por decisão da Federação Internacional de Ginástica, passou à denominação de ginástica rítmica desportiva e, finalmente, ginástica rítmica.
6 0
3 years ago
Where can I download high school textbooks online?​
MArishka [77]

probrably at the schools website but i dont know what school you go to so i would need more info

6 0
3 years ago
Two solenoids are equal in length and radius, and the cores of both are identical cylinders of iron. However, solenoid A has fou
Ira Lisetskai [31]

Answer:

\dfrac{L_A}{L_B}=16

Explanation:

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

n = Number of turns

A = Area

I = Current

Self inductance is given by

L=\mu_0n^2IA

Here, A has more turns so the self-inductance of A will be higher

For A

L_A=\mu_0n_A^2IA=\mu_0(4n_B)^2IA     [\because n_A=4n_B]

For B

L_B=\mu_0n_B^2IA

Dividing the above two equations we have

\dfrac{L_A}{L_B}=\dfrac{\mu_0(4n_B)^2IA}{\mu_0n_B^2IA}\\\Rightarrow \dfrac{L_A}{L_B}=16

\therefore \dfrac{L_A}{L_B}=16

3 0
3 years ago
Read 2 more answers
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