Question

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Answer 1

Answer:

#3: The equation needs to be in slope intercept form: y = mx + b

We can see that b (the y-intercept) is 13, because when x = 0 then y = 13

So we have y = mx + 13

Now substitute some other coordinates in this equatioin to find the slope

12.2 = m(4) + 13

-13              -13

-0.8 = m(4)

to make this easier turn the decimal into a fraction -0.8 = -8/10 = -4/5

-4/5 = m(4)

/4          /4

-1/5 = m

So the slope is -1/5 and the equation is y = -(1/5)x + 13

#4: Find the slope with this formula

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{-10 -(-4)}{8 - 4} = \frac{-6}{4} = \frac{-3}{2}$

Find the y-intercept

$y = \frac{-3}{2}x + b$

Substitute a point, such as (4, -4)

$-4 = \frac{-3}{2}(4) + b$

$-4 = \frac{-12}{2} + b$

$-4 = -6 + b$

$-4 + 6 = -6 + 6 + b$

$b = 2$

So the equation is $y = \frac{-3}{2}x + 2$

#5: The slope is given. So the equation is $y = 2x + b$

Substitute the (x, y) values given: (1, 9)

$9 = 2(1) + b$

$\frac{9}{2} = b$

So the equation is $y = 2x + \frac{9}{2}$

Step-by-step explanation: