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2 years ago

Name 4 points that would form a square with the origin at is center.

Mathematics

1 answer:

zheka24 [161]2 years ago

4 0

9514 1404 393

Answer:

(2, 3), (-3, 2), (-2, -3), (3, -2)

Step-by-step explanation:

You can pick any point you like, then rotate it around the origin to the four quadrants (or axes) by the transformation ...

(x, y) ⇒ (-y, x) . . . . . . . . . 90° rotation CCW

That is a rotation 90° CCW. Of course a rotation CW can do the same thing for you.

One possible square is ...

(2, 3), (-3, 2), (-2, -3), (3, -2)

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By pythagoreans' theorem,

Longer edge
= √(2² + 6²)
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Write an equation for your trend line?

Soloha48 [4]

Find two points on the graph that the line crosses through almost perfectly. It looks like (1,10) and (9,1) will do.

Use them to compute the slope:
m = (1 - 10) / (9 - 1)
= -9/8

Then set up the "point-slope form":
y - y0 = m * (x - x0)

You choose some point (x0, y0) that the line crosses through. We already know the line passes through (1,10) pretty well, so let's use that.

x0 = 1
y0 = 10

Now finish plugging into the equation:
y - 10 = -9/8 * (x - 1)

The above equation will work fine for an answer, but let's go a step further and solve for y.

y - 10 = -9/8x + 9/8
y = -9/8x + 9/8 + 10
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y = -9/8x + (9 + 80)/8
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