First, we write the balanced equation for this reaction:
2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂
From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:
Moles = volume (in L) * molarity
We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:
M₁V₁ = 2M₂V₂
V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L
The volume required is 173.6 mL
Answer:
Particle Symbol Mass
electron e- 0.0005486 amu
proton p+ 1.007276 amu
neutron no 1.008665
I would believe it to be 55g. A -> B YIELDS AB. So, 10g + 45g = 55g.
Answer:
No, Mercury can actually cause poisoning. That is why other metals, such as Alkaline metals, are used in making batteries
