All categories

3 years ago

Mr.pointer has as mass of 50kg. his is at the top of a 10m hill. what is his PE

Physics

1 answer:

iragen [17]3 years ago

6 0

Answer:

PE=4900J

Hope it helps please mark me as brainliest

Explanation:

P.E=m×g×h

Given m = 50 Kg , h = 10 m.

P.E=50×10×9.8

P.E=50×98=4900J

Hence increase in potential energy is 4900J.

You might be interested in

Scientist use conversion factors to express the given value of a unit different type of unit true or false

kykrilka [37]

True.

<span>Scientist use conversion factors to express the given value of a unit different type of unit</span>

4 0

3 years ago

Read 2 more answers

Which of the following is formed by constructive erosion? 1. delta 2. gully 3. rill 4. glacier

lana [24]

1. Delta, is formed by constructive erosion.

7 0

3 years ago

11 e) Can a conductor be given limitless charge? Obtain the equivalent resistance of several resistors if (a) they are in series

horsena [70]

Answer:

(e) no

(a) Rs = R' + R'' + R'''

(b) 1/Rp = 1/R' + 1/R'' + 1/R'''

Explanation:

11 e)

Practically it is not possible to give limitless charge to a conductor. It depends to the number of valence electrons.

(a) When the three resistances R'. R'' and R''' is in series combination.

Let they are connected to the voltage V and the current in each resistance is I.

According to Ohm's law

Voltage across R', V' = I R'

Voltage across R'', V'' = I R''

Voltage across R''', V''' = I R'''

So, let the equivalent resistance is Rs.

I Rs = I R' + I R'' + I R'''

Rs = R' + R'' + R'''

(b)

When the three resistances R'. R'' and R''' is in parallel combination.

Let they are connected to the voltage V and the current in each resistance is I', I''. I'''.

Current in R', I' = V/R'

Current in R'', I'' = V/R''

Current in R''', I''' = V/R'''

The equivalent resistance is Rp.

V/Rp = V/R' + V/ R'' + V/R'''

1/Rp = 1/R' + 1/R'' + 1/R'''

6 0

3 years ago

A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are

igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

$\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2$

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

$I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2$

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

$T = I\alpha = 0.303*0.6454 = 0.196 Nm$

So the force acting on the other end to generate this torque mush be:

$F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N$

4 0

3 years ago

Consider a high-pressure gas cylinder (made of kryptonite, of course), which contains one mole of H2 gas at a temperature of 750

stich3 [128]

Answer:

asi que sobre todo lol siento soy mexican y agora no se Como escribir en ingles

Explanation:

soi aamso jodidamente lol siento que me enfrie want thig ror you

4 0

3 years ago