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3 years ago

Mr.pointer has as mass of 50kg. his is at the top of a 10m hill. what is his PE

Physics

1 answer:

iragen [17]3 years ago

6 0

Answer:

PE=4900J

Hope it helps please mark me as brainliest

Explanation:

P.E=m×g×h

Given m = 50 Kg , h = 10 m.

P.E=50×10×9.8

P.E=50×98=4900J

Hence increase in potential energy is 4900J.

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WILL GIVE BRAINLY!!!!!!! Question: if a bird flies 100 meters in two minutes what is the bird's speed

ElenaW [278]

Answer: (5/6) m/s

Explanation:

Distance = 100m

Time taken = 2 min

= 2 × 60 s

= 120 s

Speed = ?

Now,

Speed = distance / time taken

Speed = 100 / 120

Speed = (5/6) m/s

6 0

4 years ago

Read 2 more answers

A 12.0 kg block rests on an inclined plane. The plane makes an angle of 31.0° with the horizontal, and the coefficient of fricti

allochka39001 [22]

Answer:

The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

Explanation:

Given that,

Mass = 12.0 kg

Angle = 31.0°

Friction coefficient = 0.158

Mass of second block = 38.0 kg

Using formula of frictional force

$f_{\mu} = \mu N$ ....(I)

Where, N = normal force

$N = mg\cos\theta$

Put the value of N into the formula

$N =12\times9.8\times\cos 31^{\circ}$

$N=100.80\ N$

Put the value of N in equation (I)

$f_{mu}=0.158\times100.80$

$f_{mu}=15.9264\ N$

Now, Weight of second block

$W = mg$

$W=38.0\times9.8$

$W=372.4\ N$

The horizontal force is

$F = mg\sintheta$

$F=12\times9.8\times\sin 31^{\circ}$

$F=60.5684\ N$ ....(II)

(I). We need to calculate the acceleration

$a=m_{2}g-\dfrac{f_{\mu}+mg\sin\theta}{m_{1}+m_{2}}$

$a=\dfrac{372.4-(15.9264+60.5684)}{12+38}$

$a=5.92\ m/s^2$

(II). We need to calculate the tension in the rope

$m_{2}g-T=m_{2}a$

$-T=38\times5.92-38\times9.8$

$T=147.44\ N$

Hence, The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.

5 0

4 years ago

1 point

s2008m [1.1K]

Answer:

The person has no displacement

Explanation:

The given parameters are

The location of the person = The equator

The distance covered in one revolution = Total distance around the body

The total distance around the Earth = The circumference of the Earth = 40.075 kilometres

The total distance moved by the person standing at the equator during the Earths complete revolution = 40,075 kilometres

The initial location of the person in relation to a fixed point in space outside Earth at the start of the revolution = x km

The final location of the person in relation to the fixed point in space outside Earth at the completion of the revolution = x km

The displacement = Change in position = Final location - Initial location

∴ The displacement = x km - x km = 0 km.

5 0

4 years ago

A 75 kg man stands in an elevator. What will be the force that the elevator exerts on him when

Over [174]

Answer:

a is the answer I think so

6 0

3 years ago

Advances in genetic engineering show that it is possible to:_____________. 1. enhance learning and memory ability in nonhuman or

san4es73 [151]

Answer:

1. enhance learning and memory ability in nonhuman organisms.

Explanation:

Genetic engineering can be defined as the process by which scientists modify the genome of an organism using new molecular tools. The resulting organism after the modification is known as Genetically Modified Organisms (GMO).

To create this genetically modified organisms requires recombinant DNA.

Advances in genetic engineering show that it is possible to enhance learning and memory ability in nonhuman organisms through biotechnology.

3 0

4 years ago