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3 years ago

Horizontal circular motion questions:

1 answer:

7 0

1. D, constant
Force must be in the direction of the velocity to change speed.

2. B. to the center of the curvature
This allows the vehicle to complete the turn.

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What is force? In physics class eleven

spayn [35]

Answer:

Explanation:

In Physics, force is defined as: The push or pull on an object with mass that causes it to change its velocity. Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a directionForce is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.

The Force can be measured using a spring balance. The SI unit of force is Newton(N).

4 0

3 years ago

The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.

mrs_skeptik [129]

Explanation:

The orbital radius of the Earth is $r_1=1.496\times 10^{11}\ m$

The orbital radius of the Mercury is $r_2=5.79 \times 10^{10}\ m$

The orbital radius of the Pluto is $r_3=5.91 \times 10^{12}\ m$

We need to find the time required for light to travel from the Sun to each of the three planets.

(a) For Sun -Earth,

Kepler's third law :

$T_1^2=\dfrac{4\pi ^2}{GM}r_1^3$

M is mass of sun, $M=1.989\times 10^{30}\ kg$

So,

$T_1^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 1.496\times 10^{11}\\\\T_1=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times1.496\times10^{11}}\\\\T_1=2\times 10^{-4}\ s$

(b) For Sun -Mercury,

$T_2^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.79 \times 10^{10}\ m\\\\T_2=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.79 \times 10^{10}}\ m\\\\T_2=1.31\times 10^{-4}\ s$

$T_3^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.91 \times 10^{12}\\\\T_3=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.91 \times 10^{12}}\\\\T_3=1.32\times 10^{-3}\ s$

8 0

3 years ago

A jogger runs by a river with a velocity of 7 m s relative to the ground. A leaf floating on the river moves with a velocity of

Hunter-Best [27]

Answer:

The velocity of the leaf relative to the jogger is 5 m/s.

Explanation:

Given that,

Velocity of jogger wrt to the ground, $V_j=7\ m/s$

velocity of leaf wrt the ground, $v_i=2\ m/s$

We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :

$V=v_j-v_i\\\\V=7-2\\\\V=5\ m/s$

So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.

3 0

4 years ago

The acceleration of a train moving from rest and its speed reaches 36m/sec in 9 sec

jenyasd209 [6]

Answer:

4 m/s^2

Explanation:

The acceleration is defined as: Δv/Δt (the difference of the velocity over a time period in which happens that difference).

Remember that a difference is calculated by subtracting the initial value of a physical quantity from its final value.

In our case:

Δv = Vfinal - Vinitial = 36m/s - 0 m/s = 36m/s

Δt = 9s

a = Δv/Δt = 36m/s / 9s = 4m/s^2

4 0

2 years ago

Q7 Describe two types of atomic change that produce electromagnetic<br> waves.

Crank

When a neutron or a proton in the nucleus changes a gamma ray is produced (gamma rays are electromagnetic waves)

When an electron drops from a higher energy level to a lower energy level an electromagnetic wave is give off.

7 0

3 years ago