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Ainat [17]
3 years ago
8

Most of the ________ deposits in Virginia are located in the Appalachian Plateau and the Valley and Ridge provinces. A) coal B)

copper C) gold D) iron
Physics
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:d Iron

Explanation:

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A 2 microcoulomb charge is placed at a distance of 0.25 m away from a 3.6 microcoulomb charge. Describe the type of electrostati
EleoNora [17]

Answer: 1.04N

Explanation:

Given

q1 = 2*10^-6C

q2 = 3.6*10^-6C

r = 0.25m

k = 9*10^9

Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."

F =(kq1q2) / r²

F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²

F = 0.0648/0.0625

F = 1.04N

The type of electrostatic force between the charges is the repulsive force

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vlabodo [156]

Answer:the answer is A

Explanation:

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Question 6 of 10
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The diagram below shows the structural formula and 3D model of the same substance. Which substance is represented by the diagram
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Two loudspeakers emit 600 Hz Hz notes. One speaker sits on the ground. The other speaker is in the back of a pickup truck. You h
Firdavs [7]

Answer:

The truck's speed is 4.04 m/s.

Explanation:

Given that,

Emit frequency = 600 Hz

Beat = 7.00 beat/sec

We need to calculate the truck's speed

Using formula of speed

\text{frequency observed}=\text{frequency emitted}\times\dfrac{v}{v+v_{source}}

Where, v = speed of sound

Put the value into the formula

(600-7)=600\times(\dfrac{343}{343-v_{truck}})

v_{truck}=\dfrac{600\times343-593\times343}{593}

v_{truck}=4.04\ m/s

Hence, The truck's speed is 4.04 m/s.

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3 years ago
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