No of atoms in 4.8 dm³ of neon gas is determined in the following way.
Explanation:
We have given
Neon Gas=4.8dm³
At STP
1 mole of an ideal gas occupies 22.4 L(dm³) of volume.
which means that number of molecules occupy 22.4 L of volume.
So
4.8 dm³x 1 mole/22.4 dm³ = 0.214 moles Neon
0.214 moles x 6.02x10²³ atoms/mole = 1.29x10²³ atoms of Neon
No of Atoms in 4.8dm3 neon gas =1.29x10²³ atoms of Neon
To know more about this :
https://brainly.in/question/2122177
https://brainly.in/question/2419625
Electronegativity
The tendency of an atom to pull electrons towards itself is called electronegativity.
It is the tendency of an atom to attract bonding pair of electrons towards itself. These atoms which are more electronegative are able to bear a negative charge and be stable.
Unlike electropositive elements which tend to lose electrons , electronegative elements hold on tightly to the electrons.
The electronegativity is measured using the Pauling Scale where the most electronegative element of the periodic table, Fluorine , is given a value of 4 and the rest of the elements have values lower than 4 according to the trends followed by their groups and periods.
The least electronegative element of the periodic table , Cesium has a value of 0.7 on the Pauling Scale.
Electronegativity increases when we move from left to right in the periodic table and it decreases (in general) when we move down the group.
(To know more about Electronegativity: https://brainly.in/question/5742635 )
Color.
Density.
Hardness.
freezing point.
Length.
Location.
Smell.
Temperature.
Volume.
Brittleness.
Hope this helps. :)
→ 
Explanation:
- The products formed are chromic chloride and cobalt.
Chromium + Cobaltous Chloride = Chromic Chloride + Cobalt
- Type of reaction is Single Displacement (Substitution) which is there is a displacement of one atom.
Reactants used in the reaction are -
- Chromium

- Cobaltous Chloride

Products formed in the reaction are -
- Chromic Chloride

- Cobalt

Hence, the chemical reaction is as follows -
→
For balancing the above chemical equation we need to add a coefficient of 2 in front of chromium and of 3 in front of cobalt(II)chloride on right-hand-side while of 2 in front of chromium chloride and of 3 in front of carbon monoxide on left-hand-side of the equation.
Hence, the balanced equation is -
→ 