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Eduardwww [97]
3 years ago
15

A teacher uses a bow and arrow to demonstrate accuracy and precision. She shoots several arrows, aiming at the exact center of t

he target each time. The drawing below shows where her arrows hit the target
Which statement best describes her shots?
Chemistry
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:Doing your momveryhardrn

Explanation:

She is visciously suckingmynuts

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28. Scott travels north 5 miles and then goes south 3 miles before coming back due north for an additional 2 miles. What is his
liubo4ka [24]

Answer:

4 miles north

Explanation:

Initially Scott travels 5 miles north at this point his displacement is 5 miles toward north

then he goes 3 miles south. which makes his displacement 2 miles (5 - 3 = 2) towards north as north and south are opposite directions.

finally he travels 2 miles due north.so his final displacement is

2 miles + 2 miles = 4 miles towards north direction

7 0
3 years ago
Fill in the blanks: Most metals have
victus00 [196]

Answer:

Most metals have <u>luster</u> which means they <u>reflect</u> light

Explanation:

When light, which is made up of energetic photons, comes in contact with the surface of a metal, it is absorbed due to the corresponding energy gaps present between the metal orbital. The absorbed photons results in the raising of the energy levels of electrons within an atom of the metal which later drop back to a lower energy level and re-emit the photons which can now be observed as the metallic luster.

4 0
3 years ago
The reaction a(g)⇌b(g) has an equilibrium constant of 5.8 and under certain conditions has q = 336. part a what can you conclude
Vika [28.1K]

Answer:

The answer is "As Q=336, at high-temperature \Delta G_{rxn}>0 and WhenK>1,\Delta G^{\circ}_{rxn}>0."

Explanation:

The equation for the reaction is:

A(g) \leftrightharpoons  B(g)  

K=5.8\\\\Q=336

At equilibrium,

\Delta G^{\circ}_{rxn}>0=-RT \ln \ K

When k=5.8(>1), the value of \ln k would be positive

So, \Delta G^{\circ}_{rxn} is negative (< 0)

So if K > l, \Delta G^{\circ}_{rxn}

If the reaction is not in equilibrium so the equation is :

\Delta G_{rxn}>0=\Delta G^{\circ}_{rxn}+RT \ln Q

Substituting the expression:

\Delta G_{rxn}>0= (-RT \ln K) + RT \ln  Q

                 = RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature \Delta G_{rxn}>0.

5 0
3 years ago
is it a b c or d Help please i'll mark you the brainlest no links seriously it's not helpful This graph depicts the motion of a
konstantin123 [22]

Option D

The car is accelerating, because if it were at rest you wouldn't see the line, and if the car was going at constant speed (forwards or backwards) then the line would be straight.

<em>Have a luvely day!</em>

7 0
3 years ago
Read 2 more answers
A ballon begins at sea level at 1 atm. It rises in the atmosphere to where the pressure is lower, to where the pressure is .75 a
maxonik [38]

Answer:

Original volume=3L

Explanation:

Assuming the gas in the ballon is ideal and the temperature does not vary with height  we have the gas law as

PV=nRT

Here RHS is constant in both the conditions which means

PV=constant

Given P1=1 atm V1=V  P2=0.75atm V2=4L

P1V1=P2V2

1*V=0.75*4

V=3L

The initial volume of the gas is 3L

4 0
3 years ago
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