From the stoichiometry of the balanced reaction equation, the correct statement are;
- For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
- For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
- For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
<h3>What is combustion?</h3>
The term combustion refers to the burning of fossil fuels for the purpose of energy production. The equation for reaction is CH4 + 2O2 ---> CO2 + 2H2O.
Using this equation as shown, the true statements are;
- For every 1 molecule of methane CH4 that reacts, 2 molecules of H2O are produced.
- For every 20 grams of methane (CH4) that reacts, 40 grams of H2O are produced.
- For every 200 moles of methane (CH4) that reacts, 400 moles of H2O are produced.
Learn more about combustion: brainly.com/question/15117038
The outer planets are <span>Jupiter, Saturn, Uranus and Neptune while the inner planets are Mercury, Venus, Earth, and Mars. The outer planets have more moons than the inner planets because these planets are much larger than the inner ones. The inner planets are terrestrial while larger ones are called gas giants, mostly made up of gas.</span>
Combination or synthesis reaction
Ionic bonds are formed when one of the two atoms that are reacting has excess electrons and transfer the electrons to the atom that is deficient in electrons. During the formation of the ionic bond, one of the reacting atoms will donate electrons and form positive ion.
Answer:
THE VOLUME OF 0.200M CALCIUM HYDROXIDE NEEDED TO NEUTRALIZE 35 mL of 0.050 M NITRIC ACID IS 43.75 mL.
Explanation:
Using
Ca VA / Cb Vb = Na / Nb
Ca = 0.0500 M
Va = 35 mL
Cb = 0.0200 M
Vb = unknown
Na = 2
Nb = 1
Equation for the reaction:
Ca(OH)2 + 2HNO3 --------> Ca(NO3)2 + 2H2O
So therefore, we make Vb the subject of the equation and solve for it
Vb = Ca Va Nb / Cb Na
Vb = 0.0500 * 35 * 1 / 0.0200 * 2
Vb = 1.75 / 0.04
Vb = 43.75 mL
The volume of 0.02M calcium hydroxide required to neutralize 35 mL of 0.05 M nitric acid is 43.75 mL
