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Deffense [45]
2 years ago
9

How much does 200 gallons of water weigh?

Chemistry
1 answer:
Jlenok [28]2 years ago
3 0
To be able to obtain the mass of the given volume of a substance, we need data on its density since it is the mass per volume of a substance. We multiply this value to the given volume. For water, it is approximately <span>10.02 lb/gal.

Mass of water = 200 gal ( 10.02 lb/gal ) = 200.4 lb

Hope this helped.</span>
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Which ones react with HCL?
alex41 [277]

Answer:

These metals — beryllium, magnesium, calcium and strontium — react with hydrochloric acid to form a chloride and free hydrogen.

Explanation:

hope it helps don't forget to mark brainiest

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7 0
3 years ago
What is the empirical formula of a substance that contains 8.33×10−2 mol of carbon, 0.167 mol of hydrogen, and 8.32×10−2 mol of
Olegator [25]
Looks to me like C and O are virtually equal and H is double those, so:

CH_20, which is the empirical formula for carbohydrates.
6 0
3 years ago
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The force that one massive object exerts to attract another object is called .
Ghella [55]

Answer:

Gravity

Explanation:

The force that one massive object exerts to attract another object is called gravity.

4 0
2 years ago
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Ascorbic acid (H2C6H6O6; H2Asc for this problem), known as vitamin C, is a diprotic acid (Ka1= 1.0x10–5 and Ka2= 5x10–12) found
Igoryamba

Answer:

The concentrations are :

[HAsc^-]=0.000702 M

[Asc^{2-}]=5.92\times 10^{-8} M

The pH of the solution is 3.15.

Explanation:

H_2Asc\rightleftharpoons HAs^-+H^+         K_{a1}=1.0\times 10^{-5}

Initial

c                0              0

Equilibrium

c-x                x          x

K_{a1}=\frac{[HAs^-][H^+]}{[H_2Asc]}

1.0\times 10^{-5}=\frac{x\times x}{(c-x)}

1.0\times 10^{-5}=\frac{x^2}{(0.050-x)}

Solving for x:

x = 0.000702 M

[HAsc^-]=0.000702 M

HAsc^-\rightleftharpoons As^{2-}+H^+        K_{a2}=5\times 10^{-12}

Initially

x                0          0

At equilibrium ;

(x - y)            y         y

K_{a2}=\frac{[As^{2-}][H^+]}{[HAsc^-]}

5\times 10^{-12}=\frac{y\times y}{(x-y)}

5\times 10^{-12}=\frac{y^2}{(x-y)}

Putting value of x = 0.000702 M

5\times 10^{-12}=\frac{y^2}{(0.000702 -y)}

y=5.92\times 10^{-8} M

[Asc^{2-}]=5.92\times 10^{-8} M

Total concentration of [H^+]=x+y=0.000702 M+5.92\times 10^{-8} M=7.0206\times 10^{-4} M

The pH of the solution :

pH=-\log[H^+]

pH=-\log[7.0206\times 10^{-4} M}=3.15

7 0
3 years ago
What is the mass of 2.13 moles of lithium arsenate
Helga [31]
Lithium Arsenate - Li3AsO4 (160g/mol). So, it’s 2,13 mol * 160 g/mol = 340,8 g.
8 0
3 years ago
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