<span>Which reagent will be used up first? Thee answer is HCl.
We need to convert the amounts of the reactants into moles to see the limiting reactant.
48.2 g HCl ( 1 mol / 36.46 g) = 1.32 mol HCl
Since the ration is 1:4 then the limiting reactant is HCl. To react all of the MnO2 we need 3.44 mol HCl.
</span><span>How many grams of Cl2 will be produced?
</span>We use the amount of limiting reactant since it will be used up first.
1.32 mol HCl (1 mol Cl2 / 4 mol HCl) ( 70.9 g Cl2 / 1 mol Cl2) =23.4 g CL2
Atomic mass Na = 22.99 u.m.a
22.99 g ------------------ 6.02x10²³ atoms
175 g -------------------- ?? atoms
175 x (6.02x10²³) / 22.99 => 4.58x10²⁴ atoms
hope this helps!
Answer : The value of 'R' is 
Solution : Given,
At STP conditions,
Pressure = 1 atm
Temperature = 273 K
Number of moles = 1 mole
Volume = 22.4 L
Formula used : 
where,
R = Gas constant
P = pressure of gas
T = temperature of gas
V = volume of gas
n = number of moles of gas
Now put all the given values in this formula, we get the values of 'R'.
Therefore, the value of 'R' is .
I do not have my reference table out to see the periodic table but in order to achieve the answer pull out the periodic table. You now know that this element is going to be a metal because it is a good conductor of electric and is malleable. Next you will find both cesium and radon and look in between them to see which one is a metal that has an atomic number that lies between both radon and cesium
