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3 years ago

Is drawing on paper a chemical or physical change

Chemistry

2 answers:

Tatiana [17]3 years ago

3 0

Answer:5

Explanation:

pav-90 [236]3 years ago

3 0

Answer:

physical change

Explanation:

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In terms of intermolecular forces why ethanol has a much higher boiling point than ethene at standard point

leva [86]

Ethanol contains an alcohol group (-OH), which includes hydrogen bonding. Hydrogen bonding is stronger than other IMFs such as Van der Waals forces and Dipole-Dipole.

Ethene only has Van der Waals forces as it is an alkene with only C-H or C-C bonds. These means that the forces are not as strong.

Since ethanol contains hydrogen bonding, it will take a higher temperature in order to break these bonds, and thus results in a higher boiling point than ethene.

6 0

3 years ago

Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water . If of carbon dioxide is pro

yaroslaw [1]

The question is incomplete, the complete question is;

Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). If 28.2 g of carbon dioxide is produced from the reaction of 15.1 g of methane and 81.2 g of oxygen gas, Calculate the percent yield of carbon dioxide. Be sure your answer has the correct number of significant digits in it.

Answer:

71.1%

Explanation:

The balanced reaction equation must first be written;

CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (g)

Let us obtain the number of moles of carbon dioxide corresponding to 28.2 g

Number of moles = mass/ molar mass= 28.2/44.01 g/mol = 0.64 moles of CO2

Next, we obtain the limiting reactant. This is the reactant that yields the least amount of product.

For methane;

Number of moles in 15.1 g= mass/molar mass= 15.1/16gmol-1 = 0.9 moles

From the reaction equation;

1 mole of methane yields 1 mole of carbon dioxide

Hence 0.9 moles of methane yields 0.9 moles of carbon dioxide.

For oxygen

Number of moles of oxygen corresponding to 81.2 g of oxygen= mass/ molar mass= 81.2g/32gmol-1 = 2.5 moles of oxygen

From the reaction equation;

2 moles of oxygen gas yields 1 mole of carbon dioxide

2.5 moles of oxygen gas yields 2.5 × 1 /2 = 1.25 moles of carbon dioxide.

Methane is the limiting reactant.

Theoretical yield of carbon dioxide= 0.9 moles

Actual yield of carbon dioxide= 0.64 moles

% yield = actual yield/ theoretical yield × 100

% yield= 0.64/0.9 ×100

% yield = 71.1%

3 0

3 years ago

In 1897 the Swedish explorer Andree tried to reach the North Pole in a balloon. The balloon was filled with hydrogen gas. The hy

vovangra [49]

Answer:

iron = 15000 kg 95% sulfuric acid = 27646.32 kg

Explanation:

The molar volume to a gas is 22.4 L, which means that a mole of a given gas at 0°C and 1 atm will have a volume os 22.4 L.

1 m3 - 1000 L

4870 m3 - x

x = 4870 * 1000 = 4.87 *10^6 L

1 mole - 22.4 L

y mole - 4.87 * 10^6 L

y = $\frac{4.87 * 10^6}{22.4}$ = 2,17 *10^5 moles (if 100% of the H2 is used)

as 20% of it is lost, we need to know how much more we need to use.

80% - 2.17 * 10^5 moles

100% - z

z = $\frac{2.17* 10^7}{80}$ = 2,68*10^5 moles

so we would need 2.68*10^5 moles of iron and sulfuric acid.

1 mole of iron - 56 *10^-3 kg

2.68*10^5 moles - t

t= 2.68*56 *10^2 = 15000 kg

1 mole of sulfuric acid - 98 * 10^-3 kg

2.68*10^5 - u

u = 2.68*98 *10^2 = 26264 kg (if 100%)

95% - 26264 kg

100% - v

v = $\frac{26264 * 100}{95}$ = 27646.32 kg

6 0

3 years ago

Give an example of a base in chemistry

slega [8]

An example of a base in chemistry would be like soap or lye

8 0

3 years ago

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A reaction is first order. If the initial reactant concentration is 0.0200 M, and 25.0 days later the concentration is 6.25 x 10

erastova [34]

A reaction is first order. If the initial reactant concentration is 0.0200 M, and 25.0 days later the concentration is 6.25 x 10-4 M, then its half-life is:

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3 years ago