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TiliK225 [7]
3 years ago
8

Determine the number of grams of carbon-14 remaining in this sample at 17,100 years.

Chemistry
1 answer:
earnstyle [38]3 years ago
8 0

Answer: I need help

Explanation:

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iragen [17]

the answer is in the picture, btw the molar mass for the first one is wrong, it should be 77.98, and the final product is 2.32

6 0
3 years ago
Which of the followings is true about G0'? A. G0' can be determined using Keq' B. G0' indicates if a reaction can occur under no
nekit [7.7K]

Answer:

A and D are true , while B and F statements are false.

Explanation:

A) True.  Since the standard gibbs free energy is

ΔG = ΔG⁰ + RT*ln Q

where Q= [P1]ᵃ.../([R1]ᵇ...) , representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R

when the system reaches equilibrium ΔG=0 and Q=Keq

0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)

therefore the first equation also can be expressed as

ΔG = RT*ln (Q/Keq)

thus the standard gibbs free energy can be determined using Keq

B) False. ΔG⁰ represents the change of free energy under standard conditions . Nevertheless , it will give us a clue about the ΔG around the standard conditions .For example if ΔG⁰>>0 then is likely that ΔG>0 ( from the first equation) if the temperature or concentration changes are not very distant from the standard conditions

C) False. From the equation presented

ΔG⁰ = (-RT*ln Keq)

ΔG⁰>0 if Keq<1 and ΔG⁰<0 if Keq>1

for example, for a reversible reaction  ΔG⁰ will be <0 for forward or reverse reaction and the ΔG⁰ will be >0 for the other one ( reverse or forward reaction)

D) True. Standard conditions refer to

T= 298 K

pH= 7

P= 1 atm

C= 1 M for all reactants

Water = 55.6 M

5 0
3 years ago
Which one is you fav one
serious [3.7K]

Answer:

the 3rd one

Explanation:

8 0
2 years ago
Read 2 more answers
I need a Help plz! It’s my final exam!
LekaFEV [45]
Um i think gold... i think?
7 0
2 years ago
What element has 4 valence electrons and 5 electron shells?
marta [7]

Answer:  Tin (Sn)

Explanation:  The electron configuration for tin (Sn) is shown in the picture.  It's last electrons are:

5s^2 4d^10 5p^2

The valence electrons are in the 5th electron shell and include 2 each in the 5s and 5p orbitals.

8 0
3 years ago
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