Answer:
Height is 11.25m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 0
Final velocity, v = 15m/s
Acceleration due to gravity, g = 10m/s²
To find the height, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
- S represents the displacement (height) measured in meters.
<em>Making S the subject, we have;</em>
But a = g = 10m/s²
<em>Substituting into the equation, we have;</em>
S = 11.25m
<em>Therefore, the ball will reach a height of 11.25m before it begins to fall. </em>
Answer:
1.38 s
Explanation:
Use the free falling formula
T = √(L)/ g
T = √18.75/9.8
T = 1.38 s
Difference exists mainly in the label for x axis.
Explanation:
- Shapes of waveform and vibration graphs are same.
- Vibration graphs shows the particle at a single location in the path of the wave when time passes.
- Waveform graphs shows the particle at multiple locations at a single moment of time.
Answer:
1 sec
Explanation:
Horizontal distance (x) = 6m
Vertical distance (y) = 1.25m
Hang time is the duration the object is in the air before it reaches maximum height.
The time of free fall is given by
t = √2y/g
g = acceleration due to gravity
t = √(2*1.25)/9.8
t = √2.5/9.8
t = 0.5secs
Hang time = 2*0.5
= 1 sec
Answer:
True or False
Explanation:
Because.....
easy 50% chance you are right
