Answer:
The power dissipated in either one of the parallel resistors is 2 V
Explanation:
Given;
two parallel resistors, R₁ and R₂ = 2 ohms
The total resistance of the Two resistors of 2 ohms connected in parallel is;
when connected to another resistor of 1 ohm in series, the total resistance becomes;
Rt = R₁ + R₂
Rt = 1 + 1 = 2 ohms
Current in the circuit, I = voltage / total resistance
= 2 /2 = 1 A
the overall circuit has been resolved to series connection, and current flow in series circuit is constant.
Power = I²R
Thus, power dissipated in either one of the parallel 2 ohms resistors is;
Power = I²R = (1)² x 2 = 2 V
Answer:
Answer is 20
Explanation:
As we know
\Large\boxed{ \tt{}F =ma}
F=ma
Here Given
★ F = 100
★ m = 25 kg
Putting in the equation
\leadsto\tt{100=25\times\:a}⇝100=25×a
On solving
\sf{\dashrightarrow\:a = 4 \:ms^{-2}}⇢a=4ms
−2
Now the body initially is stationary therefore initial velocity (u) must be zero
u = 0
Applying Newton 1st Law of Motion :
\sf\Large\boxed{ \tt{}v =u + at}
v=u+at
Substituting the values to find final velocity at t= 5 sec
\leadsto \tt{v = 0 + 4 \times \:5}⇝v=0+4×5
\tt{ \pink{\dashrightarrow\:v = 20 \:m/s}}⇢v=20m/s
☞ Hence, the final velocity is 20 m/s
Answer
given,
discharge rate from pipe = 1000 gallons/minutes
now,
flow rate in cubic meters per second
1 gallon = 0.00378541 m³
1 min = 60 s
Q =
Q = 0.063 m³/s
flow rate in liters per minute
1 gallon = 3.78541 L
Q =
Q = 3785.41 m³/min
flow rate in cubic feet per second
1 gallon = 0.133681 ft³
1 min = 60 s
Q =
Q = 2.23 ft³/s
Answer:
1,170
Explanation:
Kinetic energy=1/2×m×velocity squared