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KIM [24]
3 years ago
8

An optical fiber can make a light beam travel in a path that is curved or twisted? True or False

Physics
2 answers:
nikklg [1K]3 years ago
5 0

Answer:

True

Explanation:

An optical fiber is like a glass tube with very small radius. The light travels through these fiber following <em>Total Internal Reflection </em>principle. The movement of the light is not affected by the external factor or the shape of the fiber as long as it is intact. Even if it is twisted or curved, the light will travel as long as the fiber is not damaged physically.

Elden [556K]3 years ago
3 0
Hello their
  
      the correct answer is true
 
          
    i hope that i have helped
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A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien
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Answer:

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Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

\phi=NBA

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\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2

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We need to calculate the induced emf

Using formula of induced emf

\epsilon=\dfrac{d\phi}{dt}

Put the value into the formula

\epsilon=\dfrac{7.85\times10^{-7}}{dt}

Put the value of emf from ohm's law

\epsilon =IR

IR=\dfrac{7.85\times10^{-7}}{dt}

Idt=\dfrac{7.85\times10^{-7}}{R}

Idt=\dfrac{7.85\times10^{-7}}{0.50}

Idt=0.00000157=1.57\times10^{-6}\ C

We know that,

Idt=dq

dq=1.57\times10^{-6}\ C

We need to calculate the voltage across the capacitor

Using formula of charge

dq=C dV

dV=\dfrac{dq}{C}

Put the value into the formula

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dV=1.57\ V

Hence, The voltage across the capacitor is 1.57 V.

5 0
3 years ago
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