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KIM [24]
3 years ago
8

An optical fiber can make a light beam travel in a path that is curved or twisted? True or False

Physics
2 answers:
nikklg [1K]3 years ago
5 0

Answer:

True

Explanation:

An optical fiber is like a glass tube with very small radius. The light travels through these fiber following <em>Total Internal Reflection </em>principle. The movement of the light is not affected by the external factor or the shape of the fiber as long as it is intact. Even if it is twisted or curved, the light will travel as long as the fiber is not damaged physically.

Elden [556K]3 years ago
3 0
Hello their
  
      the correct answer is true
 
          
    i hope that i have helped
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When an oxygen atom forms an ion, it gains two electrons. What is the electrical charge of the oxygen ion? A. +2 B. -1 C. -2 D.
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C. 2-

electrons have a negative charge, thus adding two electrons to an atom will give it a charge of 2 times -1 or -2
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3 years ago
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A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a
Verizon [17]

Answer:

The shear deformation is \Delta x=3.34\times10^{-6}\ m.

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus S = 1\times10^{9}\ N/m^2

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=\dfrac{Fl_{0}}{A\Delta x}

\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}

\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}

Put the value into the formula

\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}

\Delta x=3.34\times10^{-6}\ m

Hence, The shear deformation is \Delta x=3.34\times10^{-6}\ m.

7 0
3 years ago
Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface? Explain your
Andreyy89

Answer:

Jupiter

Explanation:

Since the mass of Jupiter is the greatest from the given choices, it will exert the most force on any object orbiting 100km above its surface.

This is compliance with the Newton's law of universal gravitation which states that "the force of attraction between two bodies is directly proportional to the magnitude of their masses and inversely proportional to the distances between them".

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The red giant Betelgeuse has a surface temperature of 3000 K and is 600 times the diameter of our sun. (If our sun were that lar
Nat2105 [25]

Answer:

Explanation:

a )

Radius of the sun = .69645 x 10⁹ m .

600 times = 600 x .69645 x 10⁹ m

= 4.1787 x 10¹¹ m .

surface area A = 4π (4.1787 x 10¹¹)²

= 219.317 x 10²²

energy radiated E = σ A Τ⁴

= 5.67 x 10⁻⁸ x 219.317 x 10²² x (3000)⁴

= 100695 x 10²⁶ J

To know the wavelength of photon emitted

\lambda_mT= b

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1.32 x 1.6 x 10⁻¹⁹ J

= 2.112 x 10⁻¹⁹ J

No of photons radiated = 100695 x 10²⁶ / 2.112 x 10⁻¹⁹

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= .476 x 10⁵⁰ .

b )

energy radiated by our sun per second

E₂ = σ A 5800⁴

energy radiated by Betelgeuse per second

E₁ = σ  x 600²A x  3000⁴

E₁ / E₂  = σ  x 600²A x  3000⁴ / σ A 5800⁴

= 36 X 10⁴ x 3⁴ x 10¹² / 58⁴ x 10⁸

= 25.76 x 10⁸ x 10⁻⁵

= 25760 times .

4 0
3 years ago
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