A stationary mass of 50 kg experiences a force of 30 N. What is the
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Answer:
The temperature after half an hour is
Solution:
As per the question;
Metabolic rate of the person is 3.0105 J/h
Temperature, T =
Mass of the water,
Time duration, t = 0.5 h = 30 min = 180 s
Now,
Heat,
Thus heat transfer in half an hour:
Now, the temperature of water after half an hour, T' is given by:
where
s = 4186 J
Answer:
specific gravity = 0.8
specific gravity of solution = 2
Explanation:
given data
rectangular block above water = 0.400 in
rectangular block below water = 1.60 in
material floats below water = 0.800 in
solution
first we get here specific gravity of block that is
specific gravity = block vol below ÷ total block vol × specific gravity water ..............1
put here value we get
specific gravity = × 1
specific gravity = 0.8
and now we get here specific gravity of solution that is express as
specific gravity of solution = total block vol ÷ block vol below × specific gravity block ........................2
put here value we get
specific gravity of solution = × 0.8
specific gravity of solution = 2