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Tatiana [17]
2 years ago
11

A radioactive sample has a count rate of 800 counts per minute. One hour later, the count rate has fallen to 100 counts per minu

te. What is the half-life of the sample?
Physics
1 answer:
katovenus [111]2 years ago
4 0
Radioactivity equation states:

N = No e^(-0.693t/t1/2) --- Where t = time, t1/2 = half-life, N = count after time t, No = Initial count

Using the values given;

100 = 800 e^(-0.693*1/t1/2)
100/800 = e^(-0.693t/t1/2)
0.125 = e^(-0.693/t1/2)
Taking natural logs on both sides;
log 0.125 = -0.693/t1/2 * log (e)
-0.9031 = -0.693/t1/2 * 0.4323
t1/2 = (-0.693*0.4323)/(-0.9031) = 0.3317 hours

Therefore, half-life of the sample is approximately 0.3317 hours

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Answer:

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e. The velocity of the 3 kg trolley = -4 m/s

Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

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t = \frac{d}{v}

now it is given as

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hope it is helpful....

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