F=m*a=>a=F/m=10000/1267=7.89 m/s²
d=v₀t+a't²/2<=>394.6=112.5*a'=>a'=3.5
a-a'=7.89-3.5=4.39 m/s²
This difference causes friction forces
We apply the second principle of dynamics: vector: F + N + G + Ff = ma (vector vectors, I can not here)
Scalar: Ox: F-Ff = ma
Oy N-mg = 0
Ff = -ma+ F =-1267*7.89+10000=-8869+10000=1131 N
This frictional force (Ff) is opposite to the traction (F)
Answer:
Freezing Point - Lower
Boiling Point - Higher
Solid- liquid transition line in the phase diagram has a negative slope, but the liquid-gas transition line has a positive slope. Since there is more air pressure at 100m it will take less to freeze the water but more to boil it since it requires a larger temperature under larger pressures
Can you please include the statement or the model?
Using the Equation:
v² = vi² + 2 · a · s → Eq.1
where,
v = final velocity
vi = initial velocity
a = acceleration
s = distance
<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,
Solving Eq.1 for acceleration,
</span></span> v² = vi² + 2 · a · s
v² = 0 + 2 · a · s
v² = 2 · a · s
Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
a = 46</span>²/2×1<span>
a = 1058 m/s</span>²
<span>Now applying Newton's 2nd law of motion,
</span>
<span>F = ma
= 0.145</span>×<span>1058
F = 153.4 N</span>
The other nation will get mad at the other nation and they could start a war
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