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3 years ago

23.06 minus 8.24 equals ??? Please help

Mathematics

2 answers:

attashe74 [19]3 years ago

8 0

Answer:

14.82

Step-by-step explanation:

Hope it helps :)

Nataly [62]3 years ago

4 0

Answer: 14.82 is the answer.

Step-by-step explanation:

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How do I simplify big improper fractions?

Elodia [21]

8 can go into 270 evenly.....90 times to be exact so the answer is 90

5 0

3 years ago

Read 2 more answers

Simplify 7^-5/6*7^-7/6

DochEvi [55]

So the rule with multiplying exponents of the same base is $x^m*x^n=x^{m+n}$ . Apply this rule here:

$7^{-\frac{5}{6}}*7^{-\frac{7}{6}}=7^{-\frac{5}{6}+{-\frac{7}{6}}}=7^{-\frac{12}{6}}=7^{-2}$

Next, the rule with converting negative exponents into positive ones is $x^{-m}=\frac{1}{x^m}$ . Apply this rule here:

$7^{-2}=\frac{1}{7^2}=\frac{1}{49}$

Your final answer is 1/49.

So an additional rule when it comes to exponents is $x^{\frac{m}{n}}=\sqrt[n]{x^m}$

In this case, your fractional exponent, x^9/7, would be converted to $\sqrt[7]{x^9}$ . However, I had just realized you can further expand this.

Remember the rule I had mentioned earlier about multiplying exponents of the same base? Well, you can apply it here:

$\sqrt[7]{x^9}=\sqrt[7]{x^7*x^2}=x\sqrt[7]{x^2}$

Your final answer would be $x\sqrt[7]{x^2}$

3 0

3 years ago

Some body can help me with a geometric mean maze

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

$x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.$

2. South-East point from the Start: By the 2nd theorem,

$x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.$

3. West point from the previous: By the 2nd theorem,

$x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.$

4. West point from the previous: By the 1st theorem,

$9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.$

5. West point from the previous: By the 2nd theorem,

$10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.$

6. North point from the previous: By the 1st theorem,

$x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.$

7. East point from the previous: By the 2nd theorem,

$x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.$

8. North point from the previous: By the 1st theorem,

$x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.$

8. West point from the previous: By the 2nd theorem,

$x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.$

9. North point from the previous: By the 1st theorem,

$12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.$

101. East point from the previous: By the 1st theorem,

$6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.$

11. East point from the previous: By the 2nd theorem,

$20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.$

12. South-east point from the previous: By the 2nd theorem,

$18^2=x\cdot 21.6\Rightarrow x=15.$

13. North point=The end.

6 0

3 years ago

The following graph represents the distance a commercial airplane travels over time, at cruising speed and an altitude of 35,000

ANEK [815]

Answer:

see the explanation

Step-by-step explanation:

The picture of the question in the attached figure

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the time in hours

y ----> the distance in miles

Find the value of k

For the point (4,2268)

$k=\frac{2,268}{4}=567\ mph$

The slope represent the speed of the airplane

The linear equation is

$y=567x$

Part 1 :

The point (0,0) represents the starting point of the aircraft, when the time and distance are equal to zero. The cruising starts when time t = 0.

Part 2 :

The point (4, 2268) represents the plane after 4 hours of cruise , and shows it has traveled a distance of 2268 miles after 4 hours

3 0

4 years ago

Someone help me with these two. I'll give you brainliest and 25 points!! MATHEMATICIANS OUT THERE HELP

mixer [17]

Hello LovingAngel!

To find the slope, you can use the formulas $\frac{rise}{run}$ as well as $\frac{y^2-y^1}{x^2 - x^1}$ . I am using the latter to calculate and ensuring my answer with the former.

[Note: (x,y) is the format for ordered pairs]

First pair: value 1:(1,5) and value 2:(2,8)
$\frac{y^2-y^1}{x^2 - x^1}$ -> $\frac{8 - 5}{2 - 1}$ -> $\frac{3}{1}$ or 3.

The slope for (1,5) and (2,8) is 3(/1).

Second pair: value 1: (3,1) value 2 (3,-1)

$\frac{y^2-y^1}{x^2 - x^1}$ -> $\frac{-1 - 1}{3 - 3}$ -> $\frac{-2}{0}$
Slope for the second pair is -2/0

Checking work with $\frac{rise}{run}$
1. Slope: 3/1, meaning rise (y) +3 and run (x) +1. (1,5) -> (1+1,5 + 3) -> (2,8) ✔
2. Slope: -2/0, meaning rise (y) -2/drop (y) 2 and run 0. (3,1) -> (3 + 0, 1 + -2) -> (3,-1) ✔

6 0

3 years ago