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The final temperature, t₂ = 30.9 °C
<h3>Further explanation</h3>
Given
24.0 kJ of heat = 24,000 J
Mass of calorimeter = 1.3 kg = 1300 g
Cs = 3.41 J/g°C
t₁= 25.5 °C
Required
The final temperature, t₂
Solution
Q = m.Cs.Δt
Q out (combustion of compound) = Q in (calorimeter)
24,000 = 1300 x 3.41 x (t₂-25.5)
t₂ = 30.9 °C
Answer:
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Explanation:
It is C 2 1 2 1
You have to 1st balance the nitrates then balance the silvers to get the coefficients
Reactants Hydrogen: 5
Products Hydrogen: 5
Reactants Carbon: 3
Products Carbon: 3
Reactants Oxygen: 4
Products Oxygen: 5
