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dusya [7]
2 years ago
10

The blank form acid compounds with hydrogen

Chemistry
1 answer:
Wewaii [24]2 years ago
7 0

Answer:

The halogens form acidic compounds with hydrogen. The halogens are the most reactive among all the nonmetals

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5) Calculate the volume, in liters, of 3.24 x 1022 molecules<br> CI2
azamat

Answer: 1.12 Liters

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{3.24\times 10^{22}}{6.023\times 10^{23}}=0.05moles

1 mol of Cl_2 occupy = 22.4 L

Thus 0.05 mol of Cl_2 will occupy = \frac{22.4}{1}\times 0.05=1.12 L

5 0
3 years ago
How do you think the invention of the microscope influenced the cell theory?
ikadub [295]
Since cells are hard to see the microscope helped them see. scientist were able to actually see cells in tissues placed under the microscope.
3 0
2 years ago
Calculate the energy required to heat 322.0g of ethanol from −2.2°C to 19.6°C . Assume the specific heat capacity of ethanol und
just olya [345]

Answer:

There is 17.1 kJ energy required

Explanation:

Step 1: Data given

Mass of ethanol = 322.0 grams

Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K

Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

Specific heat capacity = 2.44 J/g*K

Step 2: Calculate energy

Q = m*c*ΔT

⇒ m = the mass of ethanol= 322 grams

⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

There is 17.1 kJ energy required

3 0
3 years ago
14) A wavelength of radiation has a frequency of 2.10 x 1014 Hz. What is the wavelength of this radiation in nm, and
Evgesh-ka [11]

Answer:

λ = 1.43 x 10³ meters (radio waves)

Explanation:

c = f·λ => λ = c/f

λ = wavelength = ?

f = frequency = 2.10 x 10¹⁴ Hz = 2.10 x 10¹⁴ cycles/sec

c = speed of light (vacuum) = 3.0 x 10⁸m/sec

λ = c/f = 3.0 x 10⁸m/sec / 2.10 x 10¹⁴sec⁻¹ = 1.43 x 10³ meters (radio waves)

3 0
3 years ago
Why chlorine has high electroaffinity than flourine​
Aleksandr-060686 [28]

Answer:

Fluorine has seven electrons in 2p-subshell whereas chlorine has seven electrons in its 3p-subshell. 3p-subshell is relatively larger than 2p-subshell. Therefore, repulsion among the electrons will be more in the 2p-shell of fluorine than 3p-subshell in chlorine.  Due to the smaller size and thus, the greater electron-electron repulsions, fluorine will not accept an incoming electron with the same as chlorine.

7 0
2 years ago
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