1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olin [163]
3 years ago
11

Calculate the expansion work done against a constant external pressure of 0.995 atm and at a constant temperature of 19°C. Assum

e that the initial volume of dry ice is negligible and that CO2 behaves like an ideal gas.
Chemistry
1 answer:
iogann1982 [59]3 years ago
4 0

This is an incomplete question, here is a complete question.

A 19.2 g quantity of dry ice (solid carbon dioxide) is allowed to sublime (evaporate) in an apparatus. Calculate the expansion work done against a constant external pressure of 0.995 atm and at a constant temperature of 22 degrees C. Assume that the initial volume of dry ice is negligible and that CO₂ behaves like an ideal gas.

Answer : The expansion work done is, -1058.33 J

Explanation :

First we have to calculate the volume of gas.

Using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT

where,

P = pressure of gas = 0.995 atm

Conversion used : (1 atm = 760 torr)

V = volume of gas = ?

T = temperature of gas = 19^oC=273+19=292K

R = gas constant = 0.0821 L.atm/mole.K

w = mass of gas = 19.2 g

M = molar mass of carbon dioxide gas = 44 g/mole

Now put all the given values in the ideal gas equation, we get:

(0.995atm)\times V=\frac{19.2g}{44g/mole}\times (0.0821L.atm/mole.K)\times (292K)

V=\frac{19.2g}{44g/mole}\times \frac{(0.0821L.atm/mole.K)\times (292K)}{0.995atm}

V=10.5L

Now we have to calculate the work done.

Formula used :

w=-p\Delta V

where,

w = work done

p = pressure of the gas = 0.995 atm

\Delta V = volume = 10.5 L

Now put all the given values in the above formula, we get:

w=-p\Delta V

w=-(0.995atm)\times (10.5L)

w=-10.4475L.atm=-10.4475\times 101.3J=-1058.33J

conversion used : (1 L.atm = 101.3 J)

Thus, the expansion work done is, -1058.33 J

You might be interested in
What is one example of an everyday molecule?
Tamiku [17]

Answer:

Hydrogen

Explanation:

Just to provide some background, an element is a pure substance consisting of only one type of atom. An atom is the smallest constituent of matter. All elements are comprised of a single type of atom (e.g., gold is composed of gold atoms, helium of helium atoms, phosphorus phosphorus, and so on).

A molecule is a group of two or more atoms. They can be the same atom (homonuclear), such as or different atoms (heteronuclear).

Some examples of homonuclear molecules include:

Hydrogen  (H2)  

Nitrogen  (N2)  

Phosphorus  (P4)  

Some examples of heteronuclear molecules include:

Carbon dioxide  (CO2)  

Sulfuric acid  (H2SO4)  

Methane  (CH4)

4 0
2 years ago
Choose all the answers that apply.
max2010maxim [7]

Answer: has properties similar to other elements in group 18, does not react readily with other elements, is part of the noble gas group

Explanation: I’ve done on edg before

6 0
2 years ago
Help! I am in a hurry! Will get brainliest if correct!
sashaice [31]

Answer:

nonmetel

Explanation:

3 0
3 years ago
Read 2 more answers
Which of these resources isn't renewable: Sunlight Water Wind Metal
Naddik [55]

Answer:

Explanation:

metal

8 0
3 years ago
Read 2 more answers
A binary compound created by reaction of bismuth and an unknown element E contains 52.07% Bi and 47.93% E by mass. If the formul
yulyashka [42]

Answer:

Atomic mass of E is 128.24

Explanation:

  • The percentage composition by mass of an element in a compound is given by dividing the mass of the element by the total mass of the compound and expressing it as a percentage.
  • In this case; the compound Bi₂E₃

Percentage composition of bismuth = 52.07%

Percentage composition of E = 47.93%

Mass Bismuth in the compound is (2×208.9804) = 417.96 g

Therefore,

To calculate the atomic mass of E

52.07% = 417.96 g

47.93% = ?

            = (47.93 × 417.96 ) ÷ 52.07 %

            = 384.729

         E₃ = 384.729

Therefore; E = 384.729 ÷ 3

                     = 128.24  

The atomic mass of E is 128.24

6 0
3 years ago
Other questions:
  • Describe the similarities and differences between herbivores,carnivore,and omnivores​
    9·1 answer
  • Oxygen and sulfur are both in the family
    11·1 answer
  • PLS HELP
    12·1 answer
  • From the data below, calculate the total heat (in j) needed to convert 0.782 mol of gaseous ethanol at 300.0°c and 1 atm to liqu
    5·1 answer
  • Consider the group a1 element sodium atomic number 11, the group 3a element aluminum atomic number 13, and the group 7a element
    10·1 answer
  • Help me with please !!!
    8·1 answer
  • 1. The volume of a gas is 10.0 liters and its temperature is 1500 K. If the temperature is
    5·1 answer
  • What is the molar mass of (NH4)3 PO3?
    9·2 answers
  • What is the product of the unbalanced equation below?
    12·1 answer
  • A buffer was prepared by mixing 1.00 mole of ammonia and 1.00 mole of ammonium chloride to form an aqueous solution with a total
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!