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wolverine [178]
2 years ago
5

Strontium and chlorine combine in only one ratio: one strontium atom for every two chlorine atoms. Based on this

Chemistry
1 answer:
Vinvika [58]2 years ago
4 0

The combinations of Strontium and chlorine  that are possible are only those in which strontium and chlorine combine in the ratio of 1:2.

1) The possible combinations are

  • 4 strontium atoms and 8 chlorine
  • 2.7 * 10^19 strontium atoms and5.4 * 10^19 chlorine atoms

2) The combinations that are not possible are

  • 20 strontium atoms and 60 chlorine atoms
  • 130 billion strontium atoms and 195 billion chlorine

We have to work out the ratio of Strontium and chlorine in each of the given  combinations in the question. Only the combinations in which the ratio of Strontium and chlorine is 1:2 is possible.

First case:

4 strontium atoms and 8 chlorine atoms gives a Strontium and chlorine ratio of 1:2 so it is possible.

Second case:

20 strontium atoms and 60 chlorine atoms gives a Strontium and chlorine ratio of 1:3 hence it is not possible.

Third case:

2.7 * 10^19 strontium atoms and 5.4 * 10^19 chlorine atoms gives a Strontium and chlorine ratio of 1:2 hence it is possible.

Fourth case:

130 billion strontium atoms and 195 billion chlorine atoms gives a Strontium and chlorine ratio of 1:1.5 hence it is not possible.

Learn more: brainly.com/question/9743981

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An analytical chemist has determined by measurements that there are 8.5 moles of magnesium in a sample of talc. How many moles o
MrRissso [65]

There are 5.66 moles of hydrogen in the sample of talc(hydrated magnesium silicate).

Given,

Talc formula is  Mg_{3} Si_4O_{10} (OH)_2

moles of magnesium = 8.5 moles

The stoichiometry of magnesium and hydrogen is 3 : 2,

So 3 moles of magnesium is equivalent to 2 moles of hydrogen.

Then 8.5 moles of magnesium is equivalent to \frac{2}{3} *8.5=5.6666 moles

<h3>Talc </h3>

Talc(hydrated magnesium silicate), often known as talcum, is a type of clay mineral made up of hydrated magnesium silicate, having the formula Mg3Si4O10(OH)2. Baby powder is made of powdered talc, frequently mixed with corn starch. This mineral serves as a lubricant and thickening agent. It serves as a component in paint, pottery, and roofing materials. It serves as a key component in many cosmetics. It can be found as foliated to fibrous aggregates and in a remarkably uncommon crystal form. It is foliated with a two-dimensional platy form, has a flawless basal cleavage, and an irregular flat fracture.

Talc(hydrated magnesium silicate), the softest mineral, is assigned a value of 1 on the Mohs scale of mineral hardness, which is based on scratch hardness comparisons.

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4 0
2 years ago
Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and oxidising and reducing agents
KATRIN_1 [288]

Answer:

Explanation:

a) Mg + NiCl_2 \rightarrow MgCl_2 + Ni

Oxidation state of Mg changes to 0 to +2.

Oxidation state of Ni changes to +2 to 0.

Oxidation state of Cl does not change.

So, Mg is oxidized, Ni is reduced.

Mg acts as reducing agent and NiCl_2 acts as oxidizing agent.

b) PCl_3 + Cl_2 \rightarrow PCl_5

Oxidation state of P changes to +3 to +5.

Oxidation state of Cl changes to 0 to -1.

So,

P is oxidized and Cl is reduced.

PCl_3 acts as reducing agent and Cl_2 acts as oxidizing agent.

c) C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O

Oxidation state of C changes to -2 to +4.

Oxidation state of O changes to 0 to -2.

Oxidation state of H does not change.

So,

C is oxidized and O is reduced.

C_2H_4 acts as reducing agent and O_2 acts as oxidizing agent.

d) Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2

Oxidation state of Zn changes to 0 to +2.

Oxidation state of H changes to +1 to 0.

Oxidation state of S and O do not change.

So, Zn is oxidized, H is reduced.

Zn acts as reducing agent and H_2SO_4 acts as oxidizing agent

e) K_2S_2O_3 + I_2 \rightarrow K_2S_4_O6 + 2KI

Oxidation state of S changes to +2 to +2.5.

Oxidation state of I changes to 0 to -1.

Oxidation state of K and O do not change.

So, S is oxidized, I is reduced.

K_2S_2O_3 acts as reducing agent and I_2 acts as oxidizing agent.

f) 3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 4H_2O+2NO

Oxidation state of Cu changes to 0 to +2.

Oxidation state of N changes to N +5 to +2.

Oxidation state of H and O do not change.

So, Cu is oxidized, N is reduced.

Cu acts as reducing agent and HNO_3 acts as oxidizing agent

8 0
2 years ago
A 2.20 mol sample of NO 2 ( g ) is added to a 3.50 L vessel and heated to 500 K. N 2 O 4 ( g ) − ⇀ ↽ − 2 NO 2 ( g ) K c = 0.513
igor_vitrenko [27]

Answer:

[NO₂] = 0.434 M

[N₂O₄] = 0.0971 M

Explanation:

The equilibrum is:  N₂O₄(g)  ⇆  2NO₂ (g)

1 moles of nitrogen (IV) oxide is in equilibrium with 2 moles of nitrogen dioxide.

Initally we only have 2.20 moles of NO₂. So let's write the equilibrium again:

              2NO₂ (g)   ⇆   N₂O₄(g)      

Initially   2.20 mol              -

React          x                      x/2

X amount has reacted, and the half has been formed, according to stoichiometry.

Eq       (2.20-x) / 3.50L     (x/2)/ 3.50L

We divide by the volume because we need molar concentrations. Let's make the Kc's expression:

Kc = [N₂O₄] / [NO₂]²

0.513 = ((x/2)/ 3.50L) /  [(2.20-x) / 3.50L]

0.513 = ((x/2)/ 3.50L) / [(2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / [2.20-x)² / 3.50L²]

0.513 = ((x/2)/ 3.50L) / (4.84 - 4.40x + x²) / 12.25)

0.513 / 12.25 (4.84 - 4.40x + x²) = x/2 / 3.50

0.203 - 0.184x + 0.0419x² = x/2 / 3.50

3.50(0.203 - 0.184x + 0.0419x²) = x/2

7 (0.203 - 0.184x + 0.0419x²) - x = 0

1.421 - 2.288x + 0.2933x² = 0  → Quadratic formula

a = 0.2933 ;  b = -2.288 ; c = 1.421

(-b +- √(b²-4ac)) / (2a)

x₁ = 7.12

x₂ = 0.68 → We consider this value, so we can have a (+) concentration.

Concentrations in the equilibrium are:

[NO₂] = (2.20-0.68) / 3.50 = 0.434 M

[N₂O₄] = (0.68/2) / 3.50  = 0.0971 M

8 0
2 years ago
Scientists changed the genes of a tomato plant in order to produce a protein which is a natural pesticide. Why would this be cla
soldi70 [24.7K]

Answer:

The plant would be insect-resistant and improve its chances of success.

Explanation:

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2 years ago
How many atoms would fit across a human hair? *
kow [346]

A typical human hair is about 1 million carbon-12 atoms JUST IN WIDTH.

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