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sergey [27]
3 years ago
7

21.4 L of gas at 42.3 °C and 681 mm Hg are heated to 221 °C, and the pressure is changed to 248 mm Hg. What is the new volume?

Chemistry
1 answer:
Allushta [10]3 years ago
6 0

Answer:

V₂ = 90.42 L

Explanation:

Given data:

Initial volume = 21.4 L

Initial pressure = 681 mmHg (681/760=0.89 atm)

Initial temperature = 42.3 °C (42.3 +273 = 315.3 K)

Final temperature = 221°C (221+273 = 494 K)

Final volume = ?

Final pressure = 248 mmHg(248/760 =0.33 atm)

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

V₂ = P₁V₁T₂/T₁P₂

V₂ = 0.89 atm × 21.4 L × 494 K / 315.3 K × 0.33 atm

V₂ = 9408.72 L /104.05

V₂ = 90.42 L

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How many moles of H2 can be made from complete reaction of 3.0 moles of Al?
tresset_1 [31]

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Explanation:

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6 0
3 years ago
Hello!
blondinia [14]

Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

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[COCl_2]=0.015M-0.01436M=0.00064M

Regards!

5 0
3 years ago
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