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aleksandr82 [10.1K]
3 years ago
14

Consider the nuclear equation below. Superscript 124 subscript 56 B a right arrow superscript 124 subscript 55 upper C s plus qu

estion mark. Which completes the nuclear equation? Superscript 0 subscript plus 1 e. Superscript o subscript negative 1 e. Superscript 1 subscript 0 n. Superscript 1 subscript 1 upper H..
Chemistry
2 answers:
nadezda [96]3 years ago
6 0

Superscript o subscript negative 1 e.

Explanation:

The nuclear reactions is of 2 types, one is nuclear fusion and the other one is nuclear fission.

Nuclear fusion is nothing but the combining of 2 nuclei with an emission of energy along with an electron, proton or beta particle.

Nuclear fission is the break down of a nucleus into 2 or more nuclei along with an electron, proton or beta particle.

And the reaction is,

₅₆B¹²⁴  ₅₅C¹²⁴ +  ₋₁e⁰

So the blank was filled by means of a beta particle.

VLD [36.1K]3 years ago
6 0

Answer:

The Answer is C.

Explanation:

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. Find the mass of 0.159 mol silicon dioxide.​
Juliette [100K]

Answer:

9.55 grams of SiO2

Explanation:

If the mass you mean by grams:

0.159 mole x 60.08 g (Periodic table by adding both elements)

Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:

9.55 grams of SiO2

4 0
2 years ago
What is a chemical equation for the second ionization for lithium
Orlov [11]
The 2nd ionization energy is removing a 2nd electron from that resulting cation: 
<span>Li+ --> Li2+ + 1e- </span>
5 0
2 years ago
Which pair of elements are the most similar? A. Ca and F B. Na and Cl C. Ne and Ar D. K and Ca
Vinil7 [7]

Answer:

c

Explanation:

8 0
3 years ago
Researchers used a combustion method to analyze a compound used as an antiknock additive in gasoline. A 9.394 mg sample of the c
LuckyWell [14K]

Answer:

The percent composition of the compound is 90.5 % C and 9.5 % H

Explanation:

Step 1: Data given

Mass of compound = 9.394 mg

Mass  of CO2 yielded = 31.154 mg

Mass of H2O yielded = 7.977 mg

Molar mass of CO2 = 44.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate moles CO2

moles of CO2 = (0.031154 g / 44.01 g/mol) = 7.08 * 10^-4 mol CO2

Step 3: Calculate moles C

moles of C = moles of CO2 * (1 mol C / 1 mol CO2)

moles of C = 7.08 * 10^-4 mol

Step 4: Calculate moles H2O

moles of H2O = (0.007977 g / 18.02 g/mol) = 4.43 * 10^-4 mol H2O

Step 5: Calculate moles of H

moles of H = moles of H2O * (2 mol H / 1 mol H2O)

moles of H =  4.43* 10^-4 *2 = 8.86 * 10^-4 mol H

Step 6: Calculate mass of C

mass C = moles C * molar mass C

mass C = 7.08 * 10^-4 mol*12.01 g/mol

mass C = 0.0085 grams

Step 7: Calculate mass of H

mass H = moles H * molar mass H

mass H = 8.86 * 10^-4 mol*1.01 g/mol

mass H = 0.000894 grams

Step 8: Calculate total mass of compound =

0.0085 grams + 0.000894 grams = 0.009394 grams = 9.394 mg

Step 9: Calculate the percent composition:  

% C = (8.50 mg / 9.394 mg) x 100 = 90.5%  

% H = (0.894 mg / 9.394 mg) x 100 = 9.5%

The percent composition of the compound is 90.5 % C and 9.5 % H

6 0
3 years ago
The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti
Vesna [10]

Zeff = Z - S

Here, Z is the number of protons in the nucleus, that is, atomic number, and S is the number of nonvalence electrons.

For boron, the electronic configuration is 1s₂ 2s₂ 2p₄

Z = 5, S = 2

Zeff = 5-2 = +3

For O, electronic configuration is 1s₂ 2s₂ 2p₄

Z = 8, S = 2

Zeff = 8-2 = +6

Hence, the correct answer is second option, that is, +3 and +6, the Zeff of boron is smaller in comparison to O, thus, boron exhibits a bigger size than O.

3 0
3 years ago
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