Answer:
1) -COOH
2) -NH2
3) hydrogen bonds
4) dispersion forces
5) -CH3
6) hydrogen bonds
7) negative
8) negative
9) positive
Explanation:
Alanine has a <u>-COOH</u> and a <u>-NH2</u> group available to form <u>hydrogen bonds</u> with water molecules.
Although there are some potential <u>dispersion forces</u> between the terminal <u>-CH3</u> group of alanine and hexane molecules, we expect the <u>hydrogen bonds</u> between alanine and water to be stronger.
Stronger intermolecular attractive forces between alanine and water lead to a more <u>negative ΔHmix</u> and more <u>negative (smaller positive)</u> ΔHsoln for water than for hexane.
Answer: The capillary rise(h) in the glass tube is = 0.009m
Explanation:
Using the equation
h = 2Tcosθ/rpg
Given
Contact angle, θ = Zero
h = height of the glass tube=?
T = surface tension = 
r = radius of the tube = 0.1mm =0.0001m
p= density of ethanol = 
g= 
h = 
h= 0.09m
Therefore the capillary rise in the tube is 0.09m
Missing question: A possible atomic weight of Q is?
A)12.7.
B)19.0.
C)27.5
D)38.0
E)57.0.
Answer is: possible atomic weight of Q is B) 19.0.
Molecular weight of first molecule is 38.0 g/mol.
Molecular weight of second molecule is 57.0 g/mol.
Molecular weight of third molecule is 76.0 g/mol.
Molecular weight of fourth molecule is 114.0 g/mol.
All four molecular weights can be division only by 19 to get whole number:
Molecule 1 (38 ÷ 19 = 2), molecule 2 (57 ÷ 19 = 3), molecule 3 (76 ÷ 19 = 4) and molecule 4 ( 114 ÷ 19 = 6).
Molecular formulas are than Q₂, Q₃, Q₄ and Q₆.
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