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IRISSAK [1]
3 years ago
10

A car starts with a velocity of 10 m/s. It

Physics
1 answer:
Marysya12 [62]3 years ago
5 0

Explanation:

v

f

=

v

i

+

a

⋅

t

v

i

:

initial velocity

a

:

acceleration

t

:

time

v

f

:

final velocity

v

i

=

20

m

2

a

=

3

m

s

2

t

=

10

s

v

f

=

20

+

3

⋅

10

v

f

=

20

+

30

v

f

=

50

mAnswer:

v

f

=

50

m

s

Explanation:

v

f

=

v

i

+

a

⋅

t

v

i

:

initial velocity

a

:

acceleration

t

:

time

v

f

:

final velocity

v

i

=

20

m

2

a

=

3

m

s

2

t

=

10

s

v

f

=

20

+

3

⋅

10

v

f

=

20

+

30

v

f

=

50

m

s

s

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What best describes desert pavements
Gekata [30.6K]

Answer:

Explanation:

A common theory suggests that desert pavements are formed through gradual removal of sand and other fine particles by the wind and intermittent rains leaving behind the large fragments. The larger rock particles are shaken into place by actions of different agents such as rain, wind, gravity, and animals

3 0
4 years ago
Why should the substage condenser not be included in computing the magnification?
Leni [432]
The reason as to why the substage condenser does not need to be included in computing the magnification and the only component needed is the ocular lens and the objective lenses is because the condenser is only responsible for gathering light and it does not contribute with the magnification of the object under the microscope.
5 0
3 years ago
Read 2 more answers
A professor sits at rest on a stool that can rotate without friction. The rotational inertia of the professor-stool system is 4.
Anestetic [448]

Answer:

\omega=0.37 [rad/s]  

Explanation:

We can use the conservation of the angular momentum.

L=mvR

I\omega=mvR

Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.

So we will have:

(I_{proffesor - stool}+mR^{2})\omega=mvR

Now, we just need to solve it for ω.

\omega=\frac{mvR}{I_{proffesor-stool}+mR^{2}}

\omega=\frac{1.5*2.7*0.4}{4.1+1.5*0.4^{2}}      

\omega=0.37 [rad/s]  

I hope it helps you!

5 0
4 years ago
Two identical cars, one on the moon and one on the earth, have the same speed and are rounding banked turns that have the same r
Naily [24]

Answer:

The value of the centripetal forces are same.

Explanation:

Given:

The masses of the cars are same. The radii of the banked paths are same. The weight of an object on the moon is about one sixth of its weight on earth.

The expression for centripetal force is given by,

F_{c} = \dfrac{mv^{2}}{r}

where, m is the mass of the object, v is the velocity of the object and r is the radius of the path.

The value of the centripetal force depends on the mass of the object, not on its weight.

As both on moon and earth the velocity of the cars and the radii of the paths are same, so the centripetal forces are the same.

3 0
3 years ago
______is the rate of change in velocity.
shepuryov [24]

Answer:

Acceleration

Explanation:

Acceleration is the rate of change in velocity

speed is how fast an object is moving

Velocity is how fast an object is moving in the particular direction

pls mark me brainliest

6 0
3 years ago
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