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We have a problem with three different state of the ratio of flow velocity to speed of sound.
That is,
a) Mach number to evaluate is 0.2, that mean we have a subsonic state.
The equation here for lift coefficient is,
where should be expressed in Rad.
So replacing in equation for subsonic state,
b) In this situation we have a transonic state, so we need to use the Prandtl-Glauert rule,
c) For this case we have a supersonic state, so we use that equation,
Answer:
n=6.56×10¹⁵Hz
Explanation:
Given Data
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
To find
Revolutions per second
Solution
Let F be the force of attraction
let n be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by
F=mω²r......................where ω=2π n
F=m4π²n²r...............eq(i)
as the values given where
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
we have to find n from eq(i)
n²=F/(m4π²r)
For the chart, for the chart, melting would be it goes from a solid to a liquid and heat would be removed.
The frequency does the other car hear after they pass each other is 631.8 Hz.
<h3>
Frequency heard by the second car</h3>
The frequency heard by the second car is calculated as follows;
f = f'(v/v - vs)
where;
- f' is the original frequency
- f is the later frequency heard
- v is speed of sound
- vs is source speed
f = 595(343/343 - 20)
f = 631.8 Hz
Thus, the frequency does the other car hear after they pass each other is 631.8 Hz.
Learn more about frequency of car here: brainly.com/question/24338491
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