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vesna_86 [32]
3 years ago
10

Determine the length of a wind instrument, assuming that it is modeled as a closed tube and that the lowest sound that it can pl

ay has a frequency of 99 Hz. The speed of sound in air is 343m/s.
Physics
1 answer:
Alex787 [66]3 years ago
3 0

Answer:

Length, l = 0.866 meters

Explanation:

Given that,

Frequency of sound, f = 99 Hz

Speed of sound in air, v = 343 m/s

To find,

The length of a wind instrument.

Solution,

The standing wave will gets formed in wind instrument. For the closed tube, the closed tube the frequency is given by :

f=\dfrac{v}{4l}

Where

l is the length of the instrument

l=\dfrac{v}{4f}

l=\dfrac{343\ m/s}{4\times 99\ Hz}

l = 0.866 meters

So, the length of a wind instrument is 0.866 meters. Hence, this is the required solution.

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A combination of two identical resistors connected in series has an equivalent resistance of 12. ohms. What is the equivalent re
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Answer:

R1 + R2 = R = 12 for resistors in series - so R1 = R2 if they are identical

2 R1 = 12         and R1 = R2 = 6 ohms

1 / R = 1 / R1 + 1 / R2     for resistors in parallel

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tresset_1 [31]

Answer:

The  time taken is  t =  32.5 \  s

Explanation:

From the question we are told that

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    The  speed  of  second car is v_2  =  52.7 \ km/h  =  14.64 \  m/s

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The distance covered by first car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  0 m/s

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_1 * t

So

     d_t =  0 \  m/s  +  (v_1 * t )

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The distance covered by second  car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  119 m

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_2* t

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Given that the two car are now in the same position we have that

    119  + 14.64 *  t  =   0   +  (18.3 * t )

   t =  32.5 \  s

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