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Kruka [31]
3 years ago
11

How much water must be added to a 25 mL sample of 1.5 M sodium sulfate in order to make it 0.20 M?

Chemistry
1 answer:
In-s [12.5K]3 years ago
4 0

Answer:

162.5 mL

Explanation:

M1*V1 = M2*V2

M - molarity

V - volume of solution

25*1.5 = 0.20 *V2

V2 = (25*1.5)/0.20= 187.5 mL of solution 2.

We had 25 mL of solution 1,  solution 2 should have volume 187.5 mL,

so we have to add V2 - V1 = 187.5 - 25 = 162.5 mL of water, or ≈ 163 mL

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