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Yuki888 [10]
3 years ago
10

Which one of these equations is balanced? a. Zn + 2hcl --> ZnCl2 + H2 b. S8 + 24F2 --> 8SF6 

Chemistry
1 answer:
Karolina [17]3 years ago
8 0
B. It's not A cause A has 1Zn on both sides, 2Cl on both sides, but 1H on the left and 2H on the right
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What characteristic of an element’s atoms always determines the element’s identity?
dmitriy555 [2]

Answer:

Number of protons

Explanation:

There are three sub atomic particles. These are;

- Protons

- Electrons

- Neutrons

Among these three particles, only one determines the identity of the element. This is the Protons. The number of protons which is also called the atomic number determines the identity of an element. For instance, atom with one proton is Hydrogen and n other element can have atomic number of one.

6 0
3 years ago
What happens to the population growth in a logistic growth pattern as it approaches carrying capacity?
AveGali [126]
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2 years ago
Methanol (ch3oh) can be made by the reaction of co with h2: co(g)+2h2(g)⇌ch3oh(g) to maximize the equilibrium yield of methanol,
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8 0
2 years ago
You need to prepare at 2.0 mL sample of a diluted drug for injection. The total amount of the drug to be injected in this 2.0 mL
pav-90 [236]

Answer:

a) The concentration of drug in the bottle is 9.8 mg/ml

b) 0.15 ml drug solution + 1.85 ml saline.

c) 4.9 × 10⁻⁵ mol/l

Explanation:

Hi there!

a) The concentration of the drug in the bottle is 294 mg/ 30.0 ml = 9.8 mg/ml

b) The drug has to be administrated at a dose of 0.0210 mg/ kg body mass. Then, the total mass of drug that there should be in the injection for a person of 70 kg will be:

0.0210 mg/kg-body mass * 70 kg = 1.47 mg drug.

The volume of solution that contains that mass of drug can be calculated using the value of the concentration calculated in a)

If 9.8 mg of the drug is contained in 1 ml of solution, then 1.47 mg drug will be present in (1.47 mg * 1 ml/ 9.8 mg) 0.15 ml.

To prepare the injection, you should take 0.15 ml of the concentrated drug solution and (2.0 ml - 0.15 ml) 1.85 ml saline

c) In the injection there is a concentration of (1.47 mg / 2.0 ml) 0.735 mg/ml.

Let´s convert it to molarity:

0.735 mg/ml * 1000 ml/l * 0.001 g/mg* 1 mol/ 15000 g = 4.9 × 10⁻⁵ mol/l

3 0
3 years ago
What is the mass of 89.6 L of SO2 gas at STP?
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wait I have an wuestion is that high school work

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