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Yuki888 [10]
3 years ago
10

Which one of these equations is balanced? a. Zn + 2hcl --> ZnCl2 + H2 b. S8 + 24F2 --> 8SF6 

Chemistry
1 answer:
Karolina [17]3 years ago
8 0
B. It's not A cause A has 1Zn on both sides, 2Cl on both sides, but 1H on the left and 2H on the right
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In a model of an atom, where would I find a valence electron<br><br><br> Help
Snowcat [4.5K]
The valence electron is the outermost shell
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How much space does 2 x 1022 atoms of copper take up?
pashok25 [27]

Answer:

2044

Explanation:

you just multiply 1022 by 2

6 0
3 years ago
Click in the answer box to activate the palette. Use the half-reaction method to balance the following equation in acidic soluti
Rzqust [24]

Answer:

The balanced reaction in the acidic medium is:

2MnO4^-+3CN^-+2H^+\rightarrow 2MnO_2+H_2O+3CNO^-

Explanation:

CN^- + MnO4^-\rightarrow CNO^- + MnO_2

1) CN^-\rightarrow CNO^- ( oxidation)

Balance oxygen by adding water :

CN^-+H_2O\rightarrow CNO^-

Now , balance hydrogen by adding hydrogen ions on the side where hydrogen are less.

CN^-+H_2O\rightarrow CNO^-+2H^+

Add electrons to balance charge where positive charge is more.

CN^-+H_2O\rightarrow CNO^-+2H^++2e^-..[1]

2) MnO4^-\rightarrow MnO_2 (reduction)

Balance oxygen by adding water :

MnO4^-\rightarrow MnO_2+2H_2O

Now , balance hydrogen by adding hydrogen ions by adding them on the side where hydrogen are less.

MnO4^-+4H^+\rightarrow MnO_2+2H_2O..[2]

Add electrons to balance charge where positive charge is more.

MnO4^-+4H^++3e^-\rightarrow MnO_2+2H_2O..[2]

3 × [1] + 2 × [2]

The balanced reaction in the acidic medium is:

2MnO4^-+3CN^-+2H^+\rightarrow 2MnO_2+H_2O+3CNO^-

5 0
3 years ago
how is rain, hail, and sleet similar and how are they different. Image of question attached. I really need help
maxonik [38]
Its all water  and sleet and hail is ice 
7 0
3 years ago
What is the density of ammonia (NH3) at 293 K and 0.913 atm?
Anastaziya [24]

Answer:  The density of  Ammonia is 0.648 g/l

Explanation:

Density = Mass/ Volume

Mass of one mole of  Ammonia (NH3) = 17.031g

Volume =?

Using the ideal gas law we can determine the volume.

PV = nRT

P = 0.913 atm, V= ?, n = 1, R = 0.08206 L.atm/K, and T= 293K

Make V the subject of the formular, we then have;

V= nRT/ P = 1 mol x 0.08206 L.atm/ K.mol x 293 / 0.913 atm

               V = 24.04358/ 0.913 = 26.3L

Having gotten the value of Volume in this question, we then go back to solve for density.

Density = Mass/ Volume

                17.031g/ 26.3L = 0.64756 ≈ 0.648 g/l

7 0
3 years ago
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