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Arada [10]
3 years ago
9

What is the distance between points (2, 4) and (3, 1) to the nearest tenth?

Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Answer:3.2

Step-by-step explanation:

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Help please I'm almost done
LUCKY_DIMON [66]
Simple....

3x-10(x+2)=13-7x

Just solve for x.....

3x-10x-20=13-7x

-7x-20=13-7x
+7x           +7x

-20=13


NO SOLUTION.

Thus, your answer.
6 0
3 years ago
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Evaluate the expression.<br> 7^0
il63 [147K]

Answer:

Heyyy!!!!

The answer is 1.

Please read explanation it will definitely help you....

Step-by-step explanation:

Okay... Here it goes...

Basically, there is an exponent rule that says that anything to the power of 0 is 1.

I hope this helps!

7 0
2 years ago
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What is Q3 for this data set?
Kisachek [45]

The same as last time

Step-by-step explanation:

8 0
2 years ago
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Determine if the statement is true or false<br> The figures below are similar
artcher [175]

Answer:

True

Step-by-step explanation:

The polygons given have 5 sides, so the sum of their interior angles is (5-2) * 180 = 540. Next, there are 4 pairs of corresponding sides. Writing those sides as a, b, c, and d, for each pentagon, we can write

540 = a + b + c + d + missing angle

540 = a + b + c + d + missing angle

As is shown here, if a, b, c, and d are the same, 540 - (a+b+c+d) = missing angle is the same as well. Therefore, there are 5 corresponding angle pairs for the two polygons. Furthermore, because there are only 5 angles for each polygon, and because having all corresponding angles be equal makes polygons similar to each other, the polygons given are similar

7 0
3 years ago
What equation is graphed in this figure?
topjm [15]

Answer:

The third equation: y+2=-3(x-1)

Step-by-step explanation:

The two points on the line are (-1,4) and (1,-2).

Slope of the line passing through two points (x_{1},y_{1}) and (x_{2},y_{2}) is given as:

m=(y_{2} -y_{1})/ (x_{2} -x_{1})

Here, (x_{1},y_{1}) and (x_{2},y_{2}) are (-1,4) and (1,-2).

Therefore, slope is equal to, m=(-2-4 )/ (1-(-1)

                                               m=-6/2

                                               m=-3  

Now, equation of a straight line with slope m and points (x_{1},y_{1}) and (x_{2},y_{2}) is given as:

y-y_{1}=m(x-x_{1})\\y-y_{2}=m(x-x_{2})

Now, if we use the 2nd form, then x_{2}=1,y_{2}=-2.

So, the equation is given as :

y-(-2)=-3(x-1)\\y+2=-3(x-1)

                                                 

8 0
3 years ago
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