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Lyrx [107]
2 years ago
8

Describe an acid or base in terms of its relationship to protons

Chemistry
1 answer:
motikmotik2 years ago
4 0
Acids are donors of protons (H+) and bases are acceptors of protons.
For example:
1) hydrochloric acid (HCl) in reaction with water give one proton to water and become chloride anion (Cl-).
2) ammonia (NH3) Is base, in reaction with water accepts one protone and become ammonium cation (NH4+).
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Classify the following as either an element, compound, homogeneous mixture or
masya89 [10]

Answer:

<h2>Heterogeneous</h2>

Explanation:

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8 0
2 years ago
How can we prevent land pollution?​
Dominik [7]

Answer:

1. Make people aware about the concept of Reduce, Recycle and Reuse.

2. Reduce the use of pesticides and fertilizers in agricultural activities.

3. Avoid buying packages items as they will lead to garbage and end up in landfill site.

4. Ensure that you do not litter on the ground and do proper disposal of garbage.

5. Buy biodegradable products.

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7 0
1 year ago
What is the molarity of a strong acid solution with a pH of 3?
Anna35 [415]

Answer:

Since HCl is a strong acid, it completely ionizes, and the pH of HCl in solution can be found from the concentration (molarity) of the H+ ions, by definition equal to 0.100 M. (The conjugate base of the acid, which is the chloride ion Cl–, would also have a concentration of 0.100 M.) The pH is thus –log(0.100) = 1.000.

Explanation:

6 0
2 years ago
I NEED HELP PLZ HELP
topjm [15]

Answer:

A

Explanation:

6 0
2 years ago
0.785 moles of N2,fill a balloon at 1.5 atm and 301 K.<br> What is the volume of the balloon?
Tcecarenko [31]

Answer:

V = 12.93 L

Explanation:

Given data:

Number of moles = 0.785 mol

Pressure of balloon = 1.5 atm

Temperature = 301 K

Volume of balloon = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values.

V = nRT/P

V = 0.785 mol × 0.0821 atm.L/ mol.K × 301 K / 1.5 atm

V = 19.4 L /1.5

V = 12.93 L

7 0
2 years ago
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