How many grams of hydrogen gas would be needed to form 8.0 grams of water
1 answer:
N h2o = mh20/Mh20
= 8.0g/18g/mol
=0.44 mol
therefore n O = 0.44mol
therefore n H2 = 0.88 mol
m H2 = n H2 * M H2
= 0.88 mol * 2 g/mol
=1.76 g
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