Answer : The value of 'R' is 
Solution : Given,
At STP conditions,
Pressure = 1 atm
Temperature = 273 K
Number of moles = 1 mole
Volume = 22.4 L
Formula used : 
where,
R = Gas constant
P = pressure of gas
T = temperature of gas
V = volume of gas
n = number of moles of gas
Now put all the given values in this formula, we get the values of 'R'.


Therefore, the value of 'R' is
.
Answer:

Explanation:
Hello,
In this case, by knowing that the heat due to a change of temperature is given by:

Whereas Q accounts for the heat, m for the mass, Cp the heat capacity and ΔT for the change in temperature. In such a way the required heat results:

Best regards.
Answer:
Air is a collection of different gases. Mainly nitrogen, and then oxygen. Gas is loosely bound atoms of an element or collection of such in compounds above the temperature required to make them liquid, and colder to make them solid.
Explanation:
hmu if you anything els!