Answer:
The mass of the ball is 0.23 kg
Explanation:
Given that
radius ,r= 3.74 cm
Density of the milk ,ρ = 1.04 g/cm³ = 1.04 x 10⁻³ kg/cm³
Normal force ,N= 9.03 x 10⁻² N
The volume of the ball V
V= 219.13 cm³
The bouncy force on the ball = Fb
Fb = ρ V g
Fb + N = m g
m=Mass of the ball = Density x volume
m = γ V , γ =Density of the Ball
ρ V g + N = γ V g ( take g= 10 m/s²)
γ = 0.00108 kg/cm³
m = γ V
m = 0.00108 x 219.13
m= 0.23 kg
The mass of the ball is 0.23 kg
Answer:
Tension= 21,900N
Components of Normal force
Fnx= 17900N
Fny= 22700N
FN= 28900N
Explanation:
Tension in the cable is calculated by:
Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium
FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)
Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)
Ftorque= 2/3FBcostheta+ 4/3FWcostheta
Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°
Ftorque= 21900N
b) components of Normal force
Efx=FNx-FTcos(90-theta)=0 static equilibrium
Fnx=21900cos(90-55)=17900N
Fy=FNy+ FTsin(90-theta)-FB-FW=0
FNy= -FTsin(90-55)+FB+FW
FNy= -21900sin(35)+(1350+2250)×9.81=22700N
The Normal force
FN=sqrt(17900^2+22700^2)
FN= 28.900N
Answer:
i. Cv =3R/2
ii. Cp = 5R/2
Explanation:
i. Cv = Molar heat capacity at constant volume
Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT
Differentiating U with respect to T, we have
= d(3/2RT)/dT
= 3R/2
ii. Cp - Molar heat capacity at constant pressure
Cp = Cv + R
substituting Cv into the equation, we have
Cp = 3R/2 + R
taking L.C.M
Cp = (3R + 2R)/2
Cp = 5R/2
Answer:
A) The net force
Explanation:
If two forces of equal strength act on an object in opposite directions, the forces will cancel, resulting in a net force of zero and no movement.
Answer:
stress tension tensile strength
Explanation:
The maximum stress which a material can withstand when it is pulled apart is its: stress tension tensile strength.
