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zalisa [80]
2 years ago
6

What is the acceleration of a dog that runs from 3 m/s to 6 m/s over a distance of 90m?

Physics
1 answer:
KonstantinChe [14]2 years ago
6 0

Answer:

solution given:

acceleration (a)=?

initial velocity (u)=3m/s

final velocity (v)=6m/s

distance (s)=90m

we have

v²=u²+2as

substituting value

6²=3²+2*a*90

36=9+180a

36-9=180a

a=25/180

<u>a=0.1388m/s²</u>

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<u>Explanation:</u>

Given:

At 40 hours, the height of the bamboo plant is 2.1cm

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