Question

What is the acceleration of a dog that runs from 3 m/s to 6 m/s over a distance of 90m?

Answer 1

Answer:

solution given:

acceleration (a)=?

initial velocity (u)=3m/s

final velocity (v)=6m/s

distance (s)=90m

we have

v²=u²+2as

substituting value

6²=3²+2*a*90

36=9+180a

36-9=180a

a=25/180

a=0.1388m/s²