B. Bacteria
C.Earthworms
D. Humus
@CristianoRonaldo
An equation relating the length that you measure l to the ship's proper length l0 is
l =l0/y. This is further explained below.
<h3>What is an equation relating the length that you measure l to the ship's proper length l0?</h3>
Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.
In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.
Read more about Lorentz transformation
brainly.com/question/16284701
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This is a classic example of conservation of energy. Assuming that there are no losses due to friction with air we'll proceed by saying that the total energy mus be conserved.

Now having information on the speed at the lowest point we can say that the energy of the system at this point is purely kinetic:

Where m is the mass of the pendulum. Because of conservation of energy, the total energy at maximum height won't change, but at this point the energy will be purely potential energy instead.

This is the part where we exploit the Energy's conservation, I'm really insisting on this fact right here but it's very very important, The totam energy Em was

It hasn't changed! So inserting this into the equation relating the total energy at the highest point we'll have:

Solving for h gives us:

It doesn't depend on mass!
Answer:
physical because chemical always reacts
The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C
<h3>Coulomb's law equation </h3>
F = Kq₁q₂ / r²
Where
- F is the force of attraction
- K is the electrical constant
- q₁ and q₂ are two point charges
- r is the distance apart
<h3>How to determine the second charge </h3>
- Charge 1 (q₁) = –6×10¯⁶ C
- Electric constant (K) = 9×10⁹ Nm²/C²
- Distance apart (r) = 0.05 m
- Force (F) = 65 N
F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Divide both side by Kq₁
q₂ = Fr² / Kq₁
q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)
q₂ = +3.0×10¯⁶ C (since the force is attractive)
Learn more about Coulomb's law:
brainly.com/question/506926